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adelina 88 [10]
1 year ago
6

Negative four and one third ÷ two and one fifth

Mathematics
2 answers:
3241004551 [841]1 year ago
5 0

The solution to the given expression negative four and one third ÷ two and one fifth is -1 32/33

<h3>Fraction division</h3>

negative four and one third ÷ two and one fifth

-4 1/3 ÷ 2 1/5

= -13/3 ÷ 11/5

  • Multiply by the reciprocal of 11/5

  • The reciprocal of 11/5 is 5/11

= -13/3 × 5/11

= (-13 × 5) / (3 × 11)

= -65 / 33

= -1 32/33

Therefore, the solution to the fraction is -1 32/33

Learn more about fraction:

brainly.com/question/11562149

#SPJ1

Naya [18.7K]1 year ago
5 0

Answer:

-65/33

Step-by-step explanation:

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Solve the following formula for b<br><br> y=6(5a+3b)<br> what does b equal
Ratling [72]

Answer:

30a + 18b

Step-by-step explanation:

6(5a+3b)

Just multiply the six in both numbers

( 6x5a) + (6x3b)

= 30a +18b

Hope this helps =)

4 0
3 years ago
Express as a difference: a+b, a+5
Tcecarenko [31]

Answer:

a - (-b), a - (-5)

Step-by-step explanation:

A double negative negative is a positive, so a - (-b) = a + b, and a - (-5) is a + 5. However, a double negative is still a difference, so this answer works.

6 0
3 years ago
A pair of shoes cost $120 but they are 25% Off;
Sever21 [200]

Answer:

Discount = $30, Final price = $90

Step-by-step explanation:

25% is one quarter. 120/4=30

One quarter of 120 is 30, so - 30 would give discounted price of $90.

Similarly you could think of it like the discounted price is 75% of the original one and do 120x0.75=90 to find 75% of 120.

Hope this helped!

3 0
3 years ago
Which of the following has a graph that is a straight line?
Amiraneli [1.4K]
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5 0
3 years ago
Read 2 more answers
Plssssss help fast!!!!Launching From a Tower
aleksandrvk [35]

Answer:

A. h = 64

B.  t = 4 -> 4 seconds

C. t = 1.5 -> 1.5 seconds

D. maximum height is 100 ft

E. The domain that makes sense for the function in this context is t

is any positive real number since time can not be negative.

Step-by-step explanation:

h = -16t2 + vt + 64

A. What tower platform height was the projectile launched from?

when the projectile was not launched, t = 0

h = -16(0)^2 + v(0) + 64 = 64

B. How long was the projectile in the air?

if the projectile lands, its height = 0 so substitute 0 for h

0 = -16(t)^2 + 48(t) + 64

  = -16(t^2 - 3t -  4)

 = -16(t - 4)(t + 1)

t = 4 or t = -1

Since time can not be negative, t = -1 can not be the answer. Therefore, the projectile lands when t = 4 or 4 seconds.

C. When did it reach its maximum height?

maximum -> t=-b/2a where in -16(t)^2 + 48(t) + 64, b = 48 and a = -16

t = -48/-32 = 1.5

D. What was its maximum height?

plug t = 1.5 into -16(t)^2 + 48(t) + 64

-16(1.5)^2 + 48(1.5) + 64 = -36 + 72 + 64 = 100

E. The domain that makes sense for the function in this context is t

is any positive real number since time can not be negative.

6 0
2 years ago
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