The correct answer is centrifugal force.
The force that pulls out from the center on a body that is in a circular motion is called centrifugal force. This force increases as the speed of motion increases. It is centrifugal force that results in a strong outward pull on your vehicle traveling around a corner.
True, hypertension is when your blood pressure is to high.
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Answer:
new_segment = [ ]
for segment in segments:
new_segment.append({'name': segment, 'average_spend': money})
print( new_segment)
Using list comprehension:
new_segment =[{'name': segment, 'average_spend': money} for segment in segments]
Using map():
def listing(a):
contain = {'name': segment, 'average_spend': money}
return contain
new_segment = [ ]
new_segment.append(map( listing, segment))
print(list(new_segment)
Explanation:
The python codes above create a list of dictionaries in all instances using for loop, for loop in list comprehension and the map function which collect two arguments .
Answer:
// here is code in C++
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{
// variables
int n,no_open=0;
cout<<"enter the number of lockers:";
// read the number of lockers
cin>>n;
// initialize all lockers with 0, 0 for locked and 1 for open
int lock[n]={};
// toggle the locks
// in each pass toggle every ith lock
// if open close it and vice versa
for(int i=1;i<=n;i++)
{
for(int a=0;a<n;a++)
{
if((a+1)%i==0)
{
if(lock[a]==0)
lock[a]=1;
else if(lock[a]==1)
lock[a]=0;
}
}
}
cout<<"After last pass status of all locks:"<<endl;
// print the status of all locks
for(int x=0;x<n;x++)
{
if(lock[x]==0)
{
cout<<"lock "<<x+1<<" is close."<<endl;
}
else if(lock[x]==1)
{
cout<<"lock "<<x+1<<" is open."<<endl;
// count the open locks
no_open++;
}
}
// print the open locks
cout<<"total open locks are :"<<no_open<<endl;
return 0;
}
Explanation:
First read the number of lockers from user.Create an array of size n, and make all the locks closed.Then run a for loop to toggle locks.In pass i, toggle every ith lock.If lock is open then close it and vice versa.After the last pass print the status of each lock and print count of open locks.
Output:
enter the number of lockers:9
After last pass status of all locks:
lock 1 is open.
lock 2 is close.
lock 3 is close.
lock 4 is open.
lock 5 is close.
lock 6 is close.
lock 7 is close.
lock 8 is close.
lock 9 is open.
total open locks are :3
