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2 years ago

Loops are frequently used to ____; that is, to make sure it is meaningful and useful.

Computers and Technology

1 answer:

vitfil [10]2 years ago

4 0

Loops are frequently used to<u> validate data </u>that is, to make sure it is meaningful and useful.

<h3>What are common blunders made by programmers in coding loops?</h3>

Forgetting to initialize and alter the loop control variable are common mistakes that programmers occasionally make. One set of instructions operates on multiple, separate sets of data. Initialized before joining a while loop.

<h3>What are the three steps that should occur in every loop?</h3>

Provide a starting value for the variable that will contain the loop.
Test the loop control variable to decide whether the loop body executes.
Alter the loop rule variable.

To learn more about Loops , refer

brainly.com/question/19344465

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You might be interested in

The ---------------initiates a message by encoding theidea (or a thought) in words or symbols and sends it to areceiver.ChannelS

saw5 [17]

Answer:

None of the given options

Explanation:

The sender initiates a message by encoding theidea (or a thought) in words or symbols and sends it to a receiver.

8 0

3 years ago

Write a loop that reads strings from standard input where the string is either "land", "air", or "water". The loop terminates wh

Setler79 [48]

The loop terminates when "xxxxx" is read in. If the word is land, the string followed by "land" get outputted. The same with air, and water.

Explanation:

int land = 0;

int air = 0;

int water = 0;

String word = "";

while(!(word.equals("xxxxx"))) {

word = stdin.next();

if(word.equals("land")) {

land++;

}else if(word.equals("air")) {

air++;

}else if(word.equals("water")) {

water++;

}

System.out.println("land:" + land);

System.out.println("air:" + air);

System.out.println("water:" + water);

5 0

3 years ago

15 points: Which type of system is used to capture and leverage the decision-making abilities of human experts?

salantis [7]

Answer:

Explanation:

4 0

2 years ago

2. A host computer with an IP address of 172.16.29.155 using a subnet mask of 255.255.255.0 and a gateway of 172.16.29.1 pings a

ASHA 777 [7]

Answer:

From the host IP address and subnet mask, you can tell that both computers are on the same network. Host 172.16.29.155 will need to send an ARP request broadcast for 172.16.29.83 to get the MAC address and update its ARP table if the host 172.16.29.83 has not already done so.

Explanation:

<h2>ADDRESS RESOLUTION PROTOCOL (ARP)</h2>

Address Resolution Protocol (ARP) is a procedure for mapping a logical address known as the IP address to a physical address known as MAC (Media Access Control) address in a local area network. The job of the ARP is essentially to translate 32-bit addresses to 48-bit addresses and vice-versa when using IP Version 4 (IPv4) to communicate on the network.

Most of the computer programs/applications use logical address (IP address) to send/receive messages, however, the actual communication happens over the physical address (MAC address) this happens in the layer 2 of the OSI model. An ARP request is a broadcast, and an ARP response is a Unicast.

Scenarios when ARP is used:

Scenario-1: The sender is a host and wants to send a packet to another host on the same network.

· Use ARP to find another host’s physical address

Scenario -2: The sender is a host and wants to send a packet to another host on another network.

· Sender looks at its routing table.

· Find the IP address of the next-hop (router) for this destination.

· Use ARP to find the router’s physical address

Scenario -3: the sender is a router and received a datagram destined for a host on another network.

· Router checks its routing table.

· Find the IP address of the next router.

· Use ARP to find the next router’s physical address.

Scenario -4: The sender is a router that has received a datagram destined for a host in the same network.

· Use ARP to find this host’s physical address.

The situation in the question above falls under scenario-1. From the host IP address and subnet mask, you can tell that both computers are on the same network. Host 172.16.29.155 will need to send an ARP request broadcast for 172.16.29.83 so to get the MAC address and update its ARP table if the host 172.16.29.83 has not already done so.

7 0

3 years ago

How many different messages can be transmitted in n microseconds using three different signals if one signal requires 1 microsec

SIZIF [17.4K]

Answer:

a_{n} = 2/3 . 2^n + 1/3 . (-1)^n

Explanation:

Let a_{n} represents number of the message that can transmitted in <em>n </em>microsecond using three of different signals.

One signal requires one microsecond for transmittal: a_{n}-1

Another signal requires two microseconds for transmittal: a_{n}-2

The last signal requires two microseconds for transmittal: a_{n}-2

a_{n}= a_{n-1} + a_{n-2} + a_{n-2} = a_{n-1} + 2a_{n-2}, n ≥ 2

In 0 microseconds. exactly 1 message can be sent: the empty message.

a_{0}= 1

In 1 microsecond. exactly 1 message can be sent (using the one signal of one microseconds:

a_{0}= 1

2- Roots Characteristic equation

Let a_{n} = r^2, a_{n-1}=r and a_{n-2}= 1

r^2 = r+2

r^2 - r - 2 =0 Subtract r+6 from each side

(r - 2)(n+1)=0 Factorize

r - 2 = 0 or r +1 = 0 Zero product property

r = 2 or r = -1 Solve each equation

Solution recurrence relation

The solution of the recurrence relation is then of the form a_{1} = a_{1 r^n 1} + a_{2 r^n 2} with r_{1} and r_{2} the roots of the characteristic equation.

a_{n} =a_{1} . 2^n + a_{2}.(-1)"

Initial conditions :

1 = a_{0} = a_{1} + a_{2}

1 = a_{1} = 2a_{1} - a_{2}

Add the previous two equations

2 = 3a_{1}

2/3 = a_{1}

Determine a_{2} from 1 = a_{1} + a_{2} and a_{1} = 2/3

a_{2} = 1 - a_{1} = 1 - 2 / 3 = 1/3

Thus, the solution of recursion relation is a_{n} = 2/3 . 2^n + 1/3 . (-1)^n

6 0

3 years ago