The probability of passing the math class of Professor Goodrum is 59%, the probability of passing Professor Cruise's physics

Mathematics

1 answer:

liq [111]1 year ago

6 0

Answer:

51%

Step-by-step explanation:

Given P(passing math) = 59%, P(passing physics) = 26%, and P(passing both) = 17%, you want to find the probability of passing only one of the courses.

<h3>Probability relations</h3>

We can record the given probabilities in a 2-way table (values shown in blue). The table is completed by making sure the totals add up (values shown in black).

The probability of passing one course and failing the other is the sum of the probabilities with a yellow background:

42% +9% = 51%

The probability of passing one or the other is 51%.

<em>Additional comment</em>

We can also get there using the relation ...

P(A+B) = P(A) +P(B) -P(AB)

The union of A and B also includes their overlap:

P(A+B) = P(AB') +P(A'B) +P(AB)

In other words, the probability of interest is ...

P(AB') +P(A'B) = P(A) +P(B) -2×P(AB) = 59% +26% -2(17%)

P(AB') +P(A'B) = 51%

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koban [17]

So
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180=3x+2y

she wants to spend 15 dollars more on sisters than nephews
so
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we have
180=3x+2y and
x=15+y
subsitute 15+y for x

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180=45+3y+2y
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3 years ago

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sdas [7]

Answer:

P = 7/3 and q = 0

Step-by-step explanation:

The given parameters are;

The endpoints of the segment are, (3, -4) and (1, 2)

The points that trisect the given points are P and Q with coordinates (p, -2) and (5/3, q) respectively

Therefore, we have;

The first point of the trisection cuts 1/3 of the length from one point and the second point of the trisection cuts 2/3 of the length from the same point

The coordinates of P or Q = (3 - (3 - 1)/3, -4 - (-4 - 2)/3) = (7/3 , -2)

Therefore, given that the y-coordinate value of the derived point coincides with the y-coordinate value of the point P, (p, -2) and there is only one point with x = -2 on the line, we have that the coordinate of the point P is (p, -2) = (7/3 , -2)

∴ P = 7/3

Similarly we have the second point of the trisection, Q, given as follows;

We are already given the x-coordinate value of the point Q as the 5/3 in (5/3, q)

Point Q = (5/3, q) = (3 - 2×(3 - 1)/3, -4 - 2×(-4 - 2)/3) = (5/3 , 0)

Point Q = (5/3, q) = (5/3 , 0)

∴ q = 0.

3 0

3 years ago

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kvasek [131]

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