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Bad White [126]
1 year ago
9

The probability of passing the math class of Professor Goodrum is 59%, the probability of passing Professor Cruise's physics

Mathematics
1 answer:
liq [111]1 year ago
6 0

Answer:

  51%

Step-by-step explanation:

Given P(passing math) = 59%, P(passing physics) = 26%, and P(passing both) = 17%, you want to find the probability of passing only one of the courses.

<h3>Probability relations</h3>

We can record the given probabilities in a 2-way table (values shown in blue). The table is completed by making sure the totals add up (values shown in black).

The probability of passing one course and failing the other is the sum of the probabilities with a yellow background:

  42% +9% = 51%

The probability of passing one or the other is 51%.

__

<em>Additional comment</em>

We can also get there using the relation ...

  P(A+B) = P(A) +P(B) -P(AB)

The union of A and B also includes their overlap:

  P(A+B) = P(AB') +P(A'B) +P(AB)

In other words, the probability of interest is ...

  P(AB') +P(A'B) = P(A) +P(B) -2×P(AB) = 59% +26% -2(17%)

  P(AB') +P(A'B) = 51%

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ANSWER

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EXPLANATION



The given inequality is,

|2n + 5|  \:  >  \: 1


By the definition of absolute value,



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We divide through by negative 1, in the first part of the inequality and reverse the sign to get,

2n + 5 \:   <   \:  - 1 \: or \: (2n + 5) \:  >  \: 1

We simplify now to get,

2n   \:   <   \:  - 1 - 5 \: or \: 2n  \:  >  \: 1 - 5


2n   \:   <   \:  - 6 \: or \: 2n  \:  >  \:  - 4


Divide through by 2 to obtain,

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