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Bad White [126]
1 year ago
9

The probability of passing the math class of Professor Goodrum is 59%, the probability of passing Professor Cruise's physics

Mathematics
1 answer:
liq [111]1 year ago
6 0

Answer:

  51%

Step-by-step explanation:

Given P(passing math) = 59%, P(passing physics) = 26%, and P(passing both) = 17%, you want to find the probability of passing only one of the courses.

<h3>Probability relations</h3>

We can record the given probabilities in a 2-way table (values shown in blue). The table is completed by making sure the totals add up (values shown in black).

The probability of passing one course and failing the other is the sum of the probabilities with a yellow background:

  42% +9% = 51%

The probability of passing one or the other is 51%.

__

<em>Additional comment</em>

We can also get there using the relation ...

  P(A+B) = P(A) +P(B) -P(AB)

The union of A and B also includes their overlap:

  P(A+B) = P(AB') +P(A'B) +P(AB)

In other words, the probability of interest is ...

  P(AB') +P(A'B) = P(A) +P(B) -2×P(AB) = 59% +26% -2(17%)

  P(AB') +P(A'B) = 51%

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Sunny_sXe [5.5K]

Answer:

option A

Step-by-step explanation:

We can find the standard form by expanding the equation:

y = 3(x-4)^2 - 22

y = 3(x^2 - 8x + 16) - 22

y = 3x^2 - 24x + 48 - 22

y= 3x^2 - 24x + 26

So the correct option is option A

8 0
3 years ago
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11. If you want to enlarge a square with area 36 square inches
larisa86 [58]

Answer:

e. 72 inches

Step-by-step explanation:

Well, firstly to find the lengths of the sides, we would have to find the square root of 36 (which is 6, as 6x6=36).

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Now we know the length of one side, we can do 18x4 (because as we all know, squares have 4 sides) to find the perimeter.

18x4=72 inches. This means the answer is option e.

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3 years ago
HURRY PLEASEE!!!! TAKING AN EXAM !! AND ITS TIMED!!! WILL GIVE BRAINLIEST!!
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Answer:

B (x+7, y-6)

Step-by-step explanation:

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3 years ago
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1/7 times x = 1<br> 5/4 times x=1<br> 3 1/2 times x=1<br> 5/7 times x=1
antiseptic1488 [7]
( i )

=  > \frac{1}{7}  \times x = 1 \\  \\  \\  \\  =  >  \frac{1}{7}  \times 7  \times x = 1 \times 7 \\  \\  \\  \\  =  > x = 7



( ii ) :


=  >  \frac{5}{4}  \times x = 1 \\  \\  \\  \\  =  >  \frac{5}{4}  \times  \frac{4}{5}   \times  x = 1 \times  \frac{4}{5}  \\  \\  \\  \\  = > x =  \frac{4}{5}



( iii ) :


=  >  3\frac{1}{2}    \times x = 1 \\  \\  \\  \\   =  >  \frac{7}{2}  \times x = 1 \\  \\  \\  \\  =  >  \frac{7}{2}  \times  \frac{2}{7}  \times x = 1 \times  \frac{2}{7}  \\  \\  \\  \\  =  > x =  \frac{2}{7}



( iv ) :


\frac{5}{7}  \times x = 1 \\  \\  \\  \\  =  >  \frac{5}{7}  \times  \frac{7}{5}  \times x = 1 \times  \frac{7}{5}  \\  \\  \\  \\  =  > x =  \frac{7}{5}
5 0
3 years ago
Simplify the expression 6×2/(-14) + 9 × 2
Ksenya-84 [330]
Use order of operations from left to right
• and / first
+ and - second

[6•2/(-14)]. +(9•2)=
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(-6+126)/7=
120/7

7 0
3 years ago
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