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Softa [21]
1 year ago
9

Amy spends 30% of her money on a

Mathematics
1 answer:
ioda1 year ago
8 0

Answer:

£2.00

Step-by-step explanation:

Badly worded, as they oftena are! But to me it means

30% spent

60% saved (I.e also taken away and put somewhere else)

10% leftover equals 20p

So 20p equals 10% of what she originally had, so 100% must be £2.00, does that make sense?

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Slope of the line =(7- -5) / (-3-1) = 12 / -4 = -3

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b  rearrange to slope-intercept form:-
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5 0
3 years ago
Find the volume of a regular box with dimensions 7" × 12" × 4".
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336" - You are to times all of them together to get your answer. Dont forget to put the inches.

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2 years ago
Five more than the product of two and a number, decreased by seven;
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Answer:

First, write the expression

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5 0
3 years ago
Read 2 more answers
A quality analyst of a tennis racquet manufacturing plant investigates if the length of a junior's tennis racquet conforms to th
Burka [1]

Answer:

Confidence interval : 21.506 to 24.493

Step-by-step explanation:

A quality analyst selects twenty racquets and obtains the following lengths:

21, 25, 23, 22, 24, 21, 25, 21, 23, 26, 21, 24, 22, 24, 23, 21, 21, 26, 23, 24

So, sample size = n =20

Now we are supposed to find Construct a 99.9% confidence interval for the mean length of all the junior's tennis racquets manufactured at this plant.

Since n < 30

So we will use t-distribution

Confidence level = 99.9%

Significance level = α = 0.001

Now calculate the sample mean

X=21, 25, 23, 22, 24, 21, 25, 21, 23, 26, 21, 24, 22, 24, 23, 21, 21, 26, 23, 24

Sample mean = \bar{x}=\frac{\sum x}{n}

Sample mean = \bar{x}=\frac{21+25+23+22+24+21+25+21+23+ 26+ 21+24+22+ 24+23+21+ 21+ 26+23+ 24}{20}

Sample mean = \bar{x}=23

Sample standard deviation = \sqrt{\frac{\sum(x-\bar{x})^2}{n-1}}

Sample standard deviation = \sqrt{\frac{(21-23)^2+(25-23)^2+(23-23)^2+(22-23)^2+(24-23)^2+(21-23)^2+(25-23)^2+(21-23)^2+(23-23)^2+(26-23)^2+(21-23)^2+(24-23)^2+(22-23)^2+(24-23)^2+(23-23)^2+(21-23)^2+(21-23)^2+(26-23)^2+(23-23)^2+(24-23)^2}{20-1}}

Sample standard deviation= s = 1.72

Degree of freedom = n-1 = 20-1 -19

Critical value of t using the t-distribution table t_{\frac{\alpha}{2} = 3.883

Formula of confidence interval : \bar{x} \pm t_{\frac{\alpha}{2}} \times \frac{s}{\sqrt{n}}

Substitute the values in the formula

Confidence interval : 23 \pm 1.73 \times \frac{1.72}{\sqrt{20}}

Confidence interval : 23 -3.883 \times \frac{1.72}{\sqrt{20}} to 23 + 3.883 \times \frac{1.72}{\sqrt{20}}

Confidence interval : 21.506 to 24.493

Hence Confidence interval : 21.506 to 24.493

3 0
3 years ago
Read 2 more answers
A city’s population, P, is modeled by the function P(x) = 78,500( 1.02 )x where x represents the number of years after the year
Levart [38]
Population 78500
Increased by 2%
3 0
3 years ago
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