Question

Pls give answer for 9c thanks

Answer 1

Answer:

probability for 3 on a dice (P3) in one dice =

$\frac{1}{6}$

probability for even no. of a dice (Pe) =

$\frac{3}{6} = \frac{1}{2}$

Therefore, the probability of finding 3 on one dice and even on another (P) = P3 + Pe

$= \frac{1}{6} + \frac{1}{2} = \frac{1 + 3}{6} = \frac{4}{6} = \frac{2}{3}$