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Kitty [74]
1 year ago
13

Pls give answer for 9c thanks

Mathematics
1 answer:
harina [27]1 year ago
7 0

Answer:

probability for 3 on a dice (P3) in one dice =

\frac{1}{6}

probability for even no. of a dice (Pe) =

\frac{3}{6}  =  \frac{1}{2}

Therefore, the probability of finding 3 on one dice and even on another (P) = P3 + Pe

=  \frac{1}{6}  +  \frac{1}{2}  =  \frac{1 + 3}{6}  =  \frac{4}{6}  =  \frac{2}{3}

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Need help, and please answer
masya89 [10]

Answer:

7(2+x)(2-x)

Step-by-step explanation:

observe

28-7x^2=7(4-x^2)=7(2+x)(2-x)

6 0
3 years ago
Plz help me with this
forsale [732]

Answer:

\frac{31x}{30}

Step-by-step explanation:

Before adding we require the fractions to have a common denominator

The lowest common denominator of 2, 5 and 3 is 30, thus

\frac{15x}{15(2)} + \frac{6x}{6(5)} + \frac{10x}{10(3)}

= \frac{15x}{30} + \frac{6x}{30} + \frac{10x}{30}

Add the numerators leaving the denominator

= \frac{15x+6x+10x}{30} = \frac{31x}{30}

5 0
3 years ago
Read 2 more answers
Is 1/3x-2y=7 a linear function
Ann [662]

Answer:

The equation is not a linear function.

5 0
3 years ago
The hyperbolic orbit of a comet is represented on a coordinate plane with center at (0, 4). One branch has a vertex at (0, 10) a
Anuta_ua [19.1K]

Remember that

If the given coordinates of the vertices and foci have the form (0,10) and (0,14)

then

the transverse axis is the y-axis

so

the equation is of the form

(y-k)^2/a^2-(x-h)^2/b^2=1

In this problem

center (h,k) is equal to (0,4)

(0,a-k)) is equal to (0,10)

a=10-4=6

(0,c-k) is equal to (0,14)

c=14-4=10

Find out the value of b

b^2=c^2-a^2

b^2=10^2-6^2

b^2=64

therefore

the equation is equal to

<h2>(y-4)^2/36-x^2/64=1</h2><h2>the answer is option A</h2>
6 0
1 year ago
You have just arrived at summer camp. And your cabin, the counselor has each camper perform the super secret handshake with ever
PSYCHO15rus [73]
Just try to follow my description. When two persons are in the cabin, there is only 1 handshake. When a third person comes, he will have to handshake the two people who came before him. So, there will be 2 handshakes. When a fourth person comes, he would make 3 handshakes with the 3 people who came before him. When the fifth person comes, he would make 4 handshakes with the 4 people who came before him. So, you see there is a pattern. The number of handshakes is 1 less than the total number of people inside the cabin. So, if there are 14 people in the cabin, the last person to come in would have to make 13 handshakes with the 13 people who came in first. Obtaining the sum of all the handshakes starting from the 2 handshakes initially to the 13 handshakes, the sum would be

Total handshakes = 2+3+4+5+6+7+8+9+10+11+12+13
Total handshakes = 90

Therefore, there will be a total of 90 handshakes made within the cabin of 14 people.
8 0
3 years ago
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