Question

A training field is formed by joining a rectangle and two semicircles, as shown below. The rectangle is 89m long and 66m wide. Find the area of the training field. Use the value 3.14 for π , and do not round your answer. Be sure to include the correct unit in your answer.

Answer 1

The area of the training field is determined as 7,583.73 m².

Area of the training field

The area of the training field is calculated as follows;

Area of the training field = area of the rectangle + area of the semicircles

The given parameters include;

• Length of the rectangle = 89 m
• Breadth of the rectangle = 66 m

Diameter of the semicircle = breadth of the rectangle = 66 m

Area of the training field =  L x b  + ¹/₂πr²

where;

• r is radius of the circle = 33 m

Area of the training field =  (89 m x 66 m)  +  ¹/₂(3.14)(33 m)²

Area of the training field =  7,583.73 m²

Thus, the area of the training field is determined as 7,583.73 m².

Learn more about area of a rectangle here: brainly.com/question/25292087

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