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djyliett [7]
2 years ago
14

Find the area of abcd

Mathematics
1 answer:
Assoli18 [71]2 years ago
3 0

Check the picture below.

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Combine these radicals. 3/5 + 2/45
Jet001 [13]

Answer:

(3√3 + 3√10)/3√5

Step-by-step explanation:

Radical means square root.

√3/5 + √2/45 = (3√3 + 3√10)/3√5

Note : √45 = √9 × 5 = √ 9 × √ 5 = 3√5

5 0
3 years ago
(03.02 HC) Stan, Liam, and Louise are competing in a cooking competition. They all used different amounts of flour from a can co
noname [10]

Answer:

Liam

Step-by-step explanation:

First we can change 12% to 0.12 then multiply 0.12 with 5 and get 0.6, so Stan has 0.6 of the flour, and we see that 0.11 is greater than 0.7 and 0.6

4 0
3 years ago
Read 2 more answers
The height of a triangle is 3cm less than the length of its base and is area is 27m,find the height
Shkiper50 [21]
Area of a triangle=bh/2

27= x(x-3)/2
27= (x^2-3x)/2
54= x^2-3x
x^2-3x-54=0
(x-9)(x+6)=0

x=9, x=-6.
In this case, x must equal 9 since the base cannot be a negative number.

Final answer: Height=6 m
6 0
4 years ago
Please help!!!! The roots of x^2-2x-2=0 are A.1+square root of 3 B.1+square root of 12 or C.No real roots
den301095 [7]

Answer:

A

Step-by-step explanation:

We have the equation:

x^2-2x-2=0

We can use the quadratic formula. In this case, a = 1, b = -2, and c = -2. Hence:

\displaystyle x=\frac{-(-2)\pm\sqrt{(-2)^2-4(1)(-2)}}{2(1)}

Evaluate:

\displaystyle x=\frac{2\pm\sqrt{12}}{2}

Simplify:

\sqrt{12}=\sqrt{4}\cdot\sqrt{3}=2\sqrt{3}

Hence:

\displaystyle x=\frac{2\pm2\sqrt{3}}{2}

Divide:

x=1\pm\sqrt3

The correct answer is A.

3 0
3 years ago
HEEEEEEEEEEEEELP (Answer correctly and you get brainly :D)
Setler79 [48]
It’s the second one :)
3 0
3 years ago
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