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jekas [21]
1 year ago
15

Solve the absolute value equation or indicate that the equation has no solution. |x-5|=4

Mathematics
1 answer:
Lelu [443]1 year ago
3 0

Step-by-step explanation:

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A bowling alley and a skating rink both offer birthday party rentals. The bowling alley costs $5 per person plus a $15 room rent
Gala2k [10]
For example: if you chose to invite 10 people the skating rink would cost a total of $50 including the room fee

If you invite 10 people to the bowling alley you would spend $65 Including the room

The answer would be to choose the skating rink
8 0
3 years ago
PLEASE HELPPPP, Graph the equations using slope intercept form. y = -3x + 8
Zolol [24]

Answer:

Slope = -3

y- intercept= (0,8)

x : 0, 8/3

y : 8, 0

8 0
3 years ago
Determine whether or not the triangles below or similar
Anastaziya [24]

Answer:

i think it is D

Step-by-step explanation:

i hope this helped!

p.s it would be cool if you gave me brainliest.

3 0
3 years ago
Given that Triangle ABC such that<br>a=8cm, b=7cm and c=9cm<br>tem and c= 9cm find Cos B​
charle [14.2K]

Answer:

We use cosine rule also called cosine law which states

c^2=a^2+b^2-2abcosC

given

a=8cm, b=7cm, c=9cm cos C?

9^2=8^+7^2-2*8*7 cos C

expand

81=64+49-112 cos C

like terms together

81-113=-112 cos C

-32=-112cos C

multiply both sides by -1

32=112cos C

divide both sides by 112

32/112=cos C

cosC=0.2857

find cos inverse of 0.2857

angle C= 73.40

4 0
3 years ago
What is the solution to sqrt 17-x=x+3? Show your work.
snow_lady [41]

Answer:

x=1

Step-by-step explanation:

Remember:

(\sqrt[n]{a})^n=a\\\\(a+b)=a^2+2ab+b^2

Given the equation \sqrt{17-x}=x+3, you need to solve for the variable "x" to find its value.

You need to square both sides of the equation:

(\sqrt{17-x})^2=(x+3)^2

17-x=(x+3)^2

Simplifying, you get:

17-x=x^2+2(x)(3)+3^2\\\\17-x=x^2+6x+9\\\\x^2+6x+9+x-17=0\\\\x^2+7x-8=0

Factor the quadratic equation. Find two numbers whose sum be 7 and whose product be -8. These are: -1 and 8:

(x-1)(x+8)=0

Then:

x_1=1\\x_2=-8

Let's check if the first solution is correct:

\sqrt{17-(1)}=(1)+3

4=4 (It checks)

Let's check if the second solution is correct:

\sqrt{17-(-8)}=(-8)+3

5\neq-5 (It does not checks)

Therefore, the solution is:

x=1

3 0
3 years ago
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