Answer:
501.
Explanation:
In Transmission Control Protocol (TCP), sending and receiving of data is done as byte. These bytes are eventually grouped into packets referred to as segment.
The sequence number of the segment if all data is sent in only one segment is the same as the first byte of that segment.
In this scenario, a user datagram connection is sending 500 bytes to a client and the first byte is numbered 501. Thus, if all data is sent in only one segment, the sequence number of the segment is 501. The 501 represents the initial segment number (ISN).
However, assuming the same data was sent in five (5) segments. The sequence number would be;
First segment (1st) = 501.
Second segment (2nd) = 1501.
Third segment (3rd) = 2501.
Fourth segment (4th) = 3501.
Fifth segment (5th) = 4501.
Answer:
There's a parking lot that is 600m² big. The lot must be able to hold at least 3 buses and 10 cars.
Each car takes up 6m² and each bus takes up 30m².
However, there can only be 60 vehicles in the lot at any given time.
The cost to park in the lot is $2.50 per day for cars and $7.50 per day for buses. The lot must make at least $75 each day to break even.
What is a possible car to bus ratio that would allow the lot to make profit?
Answer:False
Explanation:
The reason why this is false is because the CPU has a pre-determinde clock speed and increasing ram dosent help
I've included my code in the picture below. Best of luck.
Dod required a car to access data gahagsgssgsg
