Step-by-step explanation:
if you are given an equation of a form y=kx+b, k is gradient and b is y-intercept
in c you can write this equation as y=(2x/3)-2,so gradient = 2/3 and y-intercept =-2
in e:6y=2x+3
y=x/3+1/2,gradient = 1/3, y-intercept=1/2
B-9inches hope that helps
Answer:
![\sf A) \ (-4, \ 0) \ and \ \ [\dfrac{5}{2} , \ 0]](https://tex.z-dn.net/?f=%5Csf%20A%29%20%5C%20%28-4%2C%20%5C%200%29%20%5C%20and%20%5C%20%5C%20%20%5B%5Cdfrac%7B5%7D%7B2%7D%20%2C%20%5C%200%5D)
Explanation:
Given function: f(x) = -2x² - 3x + 20
To find the x-intercepts of a function, f(x) = 0
=================
-2x² - 3x + 20 = f(x)
-2x² - 3x + 20 = 0
-2x² - 8x + 5x + 20 = 0
-2x(x + 4) + 5(x + 4) = 0
(-2x + 5) (x + 4) = 0
-2x + 5 = 0, x + 4 = 0
-2x = -5, x = -4
x = -5/-2,x = -4
x = 5/2, x= -4
Coordinates: (-4, 0), (5/2, 0)
The phrase has two parts:
Five times the sum of a number and eleven, divided by
three times the sum of the number and eight
Let the number be x. Five times the sum of a number and eleven means 5 multiplied to the sum of x and 11. In expression this will be written as:
5(x + 11)Three times the sum of the number and eight means 3 multiplied to the sum of x and 8. In expression this will be written as:
3(x + 8)So, the overall expression will be: