1. you can use the multiplication sign X
2. you can use a write it as 12X
3. you can use parentheses (3)X
The answer to your question is (c) $12,425, or the third option.
subtract how much he gets in grants from how much he owes
-Hope this helped!
Given:

and,
K = 1
We would require to do the synthetic division of the above problem in order to know whether K=1 is a lower bound or not. Let's do it!
Steps of Synthetic Division:
1. Write the coefficients of the equation, and before that write 1. Like,
1 ║ 4 -2 2 4
As you can see, the coefficients of the equation are seperated by ║.
2. Drop down the first value after ║as it is. Like:
1 ║ 4 -2 2 4
:
----------------------
4
3. Multiply 4 with 1 and then place the resultant value under -2 and then add that resultant value with -2. Like
1 ║ 4 -2 2 4
:
4----------------------
4
24. Repeat Step 3 until you're done.
1 ║ 4 -2 2 4
: 4
2 ----------------------
4 2
4
1 ║ 4 -2 2 4
: 4 2
4----------------------
4
2 4
8
Now every value, +4, +2, +4, +8, under the bar(---------) is positive; therefore, it means that
K=1 is the upper bound, NOT lower bound.
Ans: K=1 is NOT a lower bound.
-i
Answer:
The answer is below
Step-by-step explanation:
The time between arrivals of small aircraft at a county airport is exponentially distributed with a mean of one hour. Round the answers to 3 decimal places.
(a) What is the probability that more than three aircraft arrive within an hour?
(b) If 30 separate one-hour intervals are chosen, what Is the probability that no interval contains more than three arrivals?
(c) Determine the length of an interval of time (in hours) such that the probability that no arrivals occur during the interval is 0.1.
Solution:
a) A poisson distribution is given by the formula:

λ = 1 hour
Therefore:
P(X > 3) = 1 - P(X < 3) = 1 - [P(X = 0) + P(X = 1) + P(X = 2) + P(x = 3)]




P(X > 3) = 1 - [0.3679+0.3679 + 0.1839 + 0.0613] = 0.019
b) Assuming 30 1 hour intervals, hence:
![P(X \leq 3)^{30}=[1-P(X\geq 30)]^{30}=(1-0.019)^{30}=0.5624](https://tex.z-dn.net/?f=P%28X%20%5Cleq%203%29%5E%7B30%7D%3D%5B1-P%28X%5Cgeq%2030%29%5D%5E%7B30%7D%3D%281-0.019%29%5E%7B30%7D%3D0.5624)
c) mean = 1 hour
mean = 1 / λ
1 = 1 / λ
λ = 1
The cumulative distribution function of a continuous variable is:


Answer:
a=b+c
Step-by-step explanation:
Dunno if that's what you're looking for, but that's what I got from what you gave