All categories

2 years ago

What is the probability that in a randomly selected game, the first goal is scored in less than 4 minutes?

1 answer:

4 0

Based on the characteristics of the distribution, the probability that the first goal is scored in less than 4 minutes is 0.

<h3>What is the probability?</h3>

For us to be able to calculate the probability that the first goal is scored in less than 4 minutes, the distribution needs to satisfy the requirements of the Central Limit Theorem(CLT).

Based on the fact that the distribution here is extremely right skewed, then it does not satisfy the requirements of CLT so the probability is 0.

First part of question:

The distribution of the time it takes for the first goal to be scored in a hockey game is known to be extremely right skewed with population mean 12 minutes and population standard deviation 8 minutes.

Find out more on the requirements of the Central Limit Theorem at brainly.com/question/18403552

#SPJ4

You might be interested in

The equation shows the relationship between x and y:

dedylja [7]

Slope is generally showed by a variable, the variable can be represented by any letter. In this case the variable is represented by x

so the slope is the number that comes before the x, so the slope of this equation is -8

So your answer is A

8 0

3 years ago

Which expression is equivalent to x - 5/3

soldier1979 [14.2K]

Answer:

$\frac{1}{3}(3x-5)$

Step-by-step explanation:

If you expand an equation you get its equivalent expression

6 0

3 years ago

The circumference of a circle with a diameter 1.8cm take pie to be 3.142

Gennadij [26K]

The formula to get the circumference is 2πr, π being pi and r being your radius.

Your r is 0.9 since the radius is half the diameter.

2πr = 2 x 3.142 x 0.9

= 5.6556cm

≈ 5.7cm

4 0

3 years ago

Suppose X, Y, and Z are random variables with the joint density function f(x, y, z) = Ce−(0.5x + 0.2y + 0.1z) if x ≥ 0, y ≥ 0, z

kompoz [17]

$f_{X,Y,Z}(x,y,z)=\begin{cases}Ce^{-(0.5x+0.2y+0.1z)}&\text{for }x\ge0,y\ge0,z\ge0\\0&\text{otherwise}\end{cases}$

is a proper joint density function if, over its support, $f$ is non-negative and the integral of $f$ is 1. The first condition is easily met as long as $C\ge0$ . To meet the second condition, we require

$\displaystyle\int_0^\infty\int_0^\infty\int_0^\infty f_{X,Y,Z}(x,y,z)\,\mathrm dx\,\mathrm dy\,\mathrm dz=100C=1\implies \boxed{C=0.01}$

b. Find the marginal joint density of $X$ and $Y$ by integrating the joint density with respect to $z$ :

$f_{X,Y}(x,y)=\displaystyle\int_0^\infty f_{X,Y,Z}(x,y,z)\,\mathrm dz=0.01e^{-(0.5x+0.2y)}\int_0^\infty e^{-0.1z}\,\mathrm dz$

$\implies f_{X,Y}(x,y)=\begin{cases}0.1e^{-(0.5x+0.2y)}&\text{for }x\ge0,y\ge0\\0&\text{otherwise}\end{cases}$

Then

$\displaystyle P(X\le1.375,Y\le1.5)=\int_0^{1.5}\int_0^{1.375}f_{X,Y}(x,y)\,\mathrm dx\,\mathrm dy$

$\approx\boxed{0.12886}$

c. This probability can be found by simply integrating the joint density:

$\displaystyle P(X\le1.375,Y\le1.5,Z\le1)=\int_0^1\int_0^{1.5}\int_0^{1.375}f_{X,Y,Z}(x,y,z)\,\mathrm dx\,\mathrm dy\,\mathrm dz$

$\approx\boxed{0.012262}$

7 0

3 years ago

Y= 4x + 2 put this on a graph please

nirvana33 [79]

....................................................

6 0

3 years ago