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White raven [17]
1 year ago
7

What is the probability that in a randomly selected game, the first goal is scored in less than 4 minutes?

Mathematics
1 answer:
kogti [31]1 year ago
4 0

Based on the characteristics of the distribution, the probability that the first goal is scored in less than 4 minutes is 0.

<h3>What is the probability?</h3>

For us to be able to calculate the probability that the first goal is scored in less than 4 minutes, the distribution needs to satisfy the requirements of the Central Limit Theorem(CLT).

Based on the fact that the distribution here is extremely right skewed, then it does not satisfy the requirements of CLT so the probability is 0.

First part of question:

The distribution of the time it takes for the first goal to be scored in a hockey game is known to be extremely right skewed with population mean 12 minutes and population standard deviation 8 minutes.

Find out more on the requirements of the Central Limit Theorem at brainly.com/question/18403552

#SPJ4

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Please help!! Thank you!!
Semmy [17]

Answer: x>-1

Step-by-step explanation:

Dotted line on the axis is covering y infinitely, so theres an inequality on x, and the line is at -1, so x should be > - 1

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2 years ago
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This is what I put in my response

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3 years ago
Identify the value of y<br><br><br> (3y+5)=-4-8y+9+77
noname [10]

Answer:

Y=7

Step-by-step explanation:

(3y+5)= -4 -8y +9 + 77

     -5    -5            

    3y= -9 - 8y + 9 + 77

           +9          -9

    3y=  -8y + 77

    +8y    +8y

      11y = 77

      11y/11    77/11

        y = 7

1. subtract 5 from both sides

2. add -9 and +9 and you get 0

3. add 8y to both sides

4. divide both sides by 11

5. you get y=7

3 0
3 years ago
Of the 345 7th graders, 40% of them<br> are in band. How many 7 graders<br> are in band?
xz_007 [3.2K]
So first you find 10% which is 34.5
Then you multiply 10% by 4 to get 40% which is = 138
3 0
2 years ago
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Part 3: Write the equation of and graph an ellipse.
tensa zangetsu [6.8K]

Answer:

Step-by-step explanation:

The center is halfway between vertices, at (4, -6).

It is also halfway between foci.

:::::

The vertices are vertically aligned, so the parabola is vertical.

General equation for a vertical ellipse:

 (y-k)²/a² + (x-h)²/b² = 1

with

 center (h,k)

 vertices (h,k±a)

 co-vertices (h±b,k)

 foci (h,k±c), c² = a²-b²

Apply your data and solve for h, k, a, and b.

center (h,k) = (4, -6)

h = 4

k = -6

vertices (4,-6±a) = (4,-6±9)

a = 9

foci (4,-6±c) = (4,-6±5√2)

b² = a² - c² = 9² - (5√2)² = 31

b = √31

The equation becomes

 (y+6)²/81 + (x-4)²/31 = 1

:::::

length of major axis = 2a = 18

length of minor axis = 2b = 2√31

8 0
2 years ago
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