A person walks a path on 3 hours.In the first hour,he walks a third of the way;on the second hour,the forth of the way and on th
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From the information: v is 64 while c is 5
Differentiate the new equation h=-16 + 64t + 5 to get
= -32t + 64.
no 13). At maximum height this derivative equals zero so: -32t + 64 = 0; -32t = -64; t=2.Hence ans is 2 secs
no 14). put t as 2 sec in the equation: h=-16 + 64t + 5. This gives
h=-16( ) + 64(2) + 5; h=-64+128+5=69. Hence h is 69ft