Answer:
Length of XM is 5.5 units.
Step-by-step explanation:
Given △XYZ where MZ is the angle bisector of ∠YZX . we have to find the length of XM.
A triangle with vertices X, Y, and Z. Side XZ is base. A line segment drawn from Z to M bisects ∠YZX into two parts ∠YZM and ∠XZM.
YZ=7 units, XZ=11 units and YM=3.5 units
By angle bisector theorem which states that an angle bisector of an angle divides the opposite side in two segments that are proportional to the another two sides of the triangle.
Hence, 
⇒ 
⇒ MX=5.5 units.
Hence, length of XM is 5.5 units.
The simplified expression is: -14s⁴-2s²+3s-3.
First group all the like terms together.
(-8s⁴)+(-6s⁴)=-14s
-2s
7s+(-4s)=3s
-3
Then put the expression back together, starting with the term that has the largest exponent, then working your way down. You would then get: -14s⁴-2s²+3s-3.
So in order for us to know the area of the square that is not covered by the circle, we need to find first both the areas of the square and the circle.
So for the area of the square it is A = sxs. And for the circle is A = pi*r^2.
Let us find the area of the square first given that the side is 3 inches.
So A = 3*3
A = 9 square inches.
Next is the area of the circle. Since the center of the circle is the same with the center of the square, the radius would be 1.5.
SO, A = (3.14)(1.5)^2
A = 2.25 (3.14)
A = 7.065 square inches.
Next, we deduct the area of circle from area of square and the result would be 1.935 <span>in². So the answer for this would be option B.
Hope this answer helps.</span>
12 *12 = 144
Therefore 12^2 = 144
What's 200 minus 50 that's your answer simple
