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Anni [7]
2 years ago
14

X + 8 = 2(0.5x + 4). Help anyone?

Mathematics
2 answers:
mote1985 [20]2 years ago
4 0

I hope this is helpful....

harina [27]2 years ago
3 0

Hope it helps. Life Goes On

.

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Cuantas galletas marias gamesa son 100g?/How many gamesa marias cookies are 100g?
jok3333 [9.3K]

Answer:i think its 10

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Can someone please help
Ivanshal [37]
Hi! The answer is 3!
5 0
3 years ago
Solve the quadratic function by completing the square. What are the missing pieces in the steps?
Sergeu [11.5K]

Answer:

x = -2; or x = -8

Step-by-step explanation:

Solve the quadratic function by completing the square. What are the missing pieces in the steps? -32=2(x^2+10)

-32+___=2(x2+10x+25)

18=2(x+5)^2

9=(x+5)^2

+-___=x+5

X=-2 or x=___

Solution:

From the first line:

-32+___=2(x2+10x+25)

Also, in the second line:

18=2(x+5)^2

Let the missing piece on line 2 be a, hence:

x² + 10x + 25 = (x + 5)² and -32 + a = 18

a = 18 + 32 = 50

-32 + 50 =2(x²+10x+25)

18 = 2(x+5)²

Dividing through by 2:

18 / 2= [2(x+5)² / 2]

9 = (x + 5)²

Taking square root of both sides:

√9 = √(x + 5)²

± 3 = x+5

Simplifying the equation to get:

3 = x + 5; -3 = x + 5

x = 3 - 5; or x = -3 - 5

x = -2; or x = -8

9 0
3 years ago
Valentina is trying to decide whether to join her school's swim team. During the summer, the team practices 4 days per week. Eac
Aloiza [94]

Answer:

4

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
parallelogram PQRS has PQ=RS=8 cm and diagonal QS= 10 cm. point F is on RS exactly 5 cm from S. let T be the intersection of PF
Doss [256]

<u>Solution-</u>

Given that,

In the parallelogram PQRS has PQ=RS=8 cm and diagonal QS= 10 cm.

Then considering ΔPQT and ΔSTF,

1-    ∠FTS ≅ ∠PTQ            ( ∵ These two are vertical angles)

2-   ∠TFS ≅ ∠TPQ            ( ∵ These two are alternate interior angles)

3-   ∠TSF ≅ ∠TQP            ( ∵ These two are also alternate interior angles)

<em>If the corresponding angles of two triangles are congruent, then they are said to be similar and the corresponding sides are in proportion.</em>

∴ ΔFTS ∼ ΔPTQ, so corresponding side lengths are in proportion.

\Rightarrow \frac{PQ}{FS} =\frac{TQ}{TS} =\frac{TP}{TF}

As QS = TQ + TS = 10 (given)

If TS is x, then TQ will be 10-x. Then putting these values in the equation

\Rightarrow \frac{PQ}{FS} =\frac{TQ}{TS}

\Rightarrow \frac{8}{5} =\frac{10-x}{x}

\Rightarrow x=3.85

∴ So TS = 3.85 cm and TQ is 10-3.85 = 6.15 cm




5 0
4 years ago
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