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likoan [24]
2 years ago
14

I need help. What does n equal.

alt="5n^{2}=7n-2" align="absmiddle" class="latex-formula">
Mathematics
2 answers:
Ede4ka [16]2 years ago
7 0

Answer:

\boxed{\sf  n= \dfrac{2}{5} ,\: n=1}

Step-by-step explanation:

\rightarrow 5n^2 = 7n -2

\rightarrow 5n^2 - 7n +2=0

\rightarrow 5n^2 - 5n -2n+2=0

\rightarrow 5n(n - 1) -2(n-1)=0

\rightarrow (5n-2)(n-1)=0

\rightarrow 5n-2= 0,\: n-1=0

\rightarrow 5n= 2,\: n=1

\rightarrow n= \dfrac{2}{5} ,\: n=1

Zanzabum2 years ago
4 0

  • \pmb{ n= \dfrac{2}{5} \:or~ n=1}

Step-by-step explanation:

\hookrightarrow\sf{5n^2 = 7n -2}\\\\\hookrightarrow\sf{5n^2 - 7n +2=0}\\\\\hookrightarrow\sf{5n^2 - (5+2)n +2=0}\\\\\hookrightarrow\sf{5n^2 - 5n -2n+2=0}\\\\\hookrightarrow\sf{ 5n(n - 1) -2(n-1)=0}\\\\\hookrightarrow\sf{ (5n-2)(n-1)=0}\\\\\hookrightarrow\sf{ 5n-2= 0\:or~ n-1=0}\\\\\hookrightarrow\sf{ 5n= 2\:or~n=1}\\\\\hookrightarrow\bold{ n= \dfrac{2}{5} \:or~ n=1}

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Answer:

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Step-by-step explanation:

Given:

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a. What are the units of What are the units of λ?

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Solution:

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                    P ( X = t ) = λ*e^(-λ*t)

                    P ( X = t ) = e^(-t/8267) / 8267

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- The probability of the decay time between years 5000 and 6000 years is:

                    P ( 5000 < X < 6000) = 1 - e^(-6000/8267) - 1 + e^(-5000/8267)

                    P ( 5000 < X < 6000) =  0.06222

- The standard deviation of the exponential distribution is given by:

                    SD(X) = 1 / λ = 8267 years

- The median decay time for an exponential distribution is given by:

                    T_1/2 = Ln(2) / λ = Ln(2)*8267

                    T_1/2 = 5730.25 years                        

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