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Bess [88]
2 years ago
14

Quadrilateral A'B'C'D' is the image of quadrilateral ABCD under a rotation about the origin, (0, 0).

Mathematics
1 answer:
Leona [35]2 years ago
8 0

The rotation of the quadrilateral ABCD about the origin (0, 0), to get the quadrilateral A'B'C'D' is 30°

<h3>How can the angle of rotation be found?</h3>

The coordinates of the vertices of rectangle ABCD are;

A(-2, 3), B(-3, 4), C(-6, 2), D(-4, 0)

The coordinates of the corresponding point <em>D'</em><em> </em>is (-3.5, -2)

The angle formed at the vertex <em>O </em>of triangle ODD' is found as follows;

OD = OD' = 4

The correct x-coordinate of point D' is therefore -√(16 - 4) = -2•√3

The length of DD' is therefore;

DD' = √((-4 - (-2•√3))² + (0 - (-2))²) = 2•√6 - 2•√2

Using cosine rule, we have;

32 - 16•√3 = 2×4² - 2×4²×cos(A)

cos(A) = (2×4² - (32 - 16•√3))/(2×4²) = √3/2

  • A = arccos(√3/2) ≈ 30°

Therefore;

  • The angle of rotation is 30°

Learn more about rotation transformation here:

brainly.com/question/24263250

#SPJ1

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Use the order of operations to simplify this expression.<br> 2 + 4(5 − 8)
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an inlet pipe and a hose together can fill the pond in 10 hours. The inlet pipe alone can complete the job in one hour less time
Annette [7]

Answer:

The hose pipe can fill the pond in 21.465 hours.

The inlet pipe can fill the pond in 20.465 hours.

Step-by-step explanation:

Given that, a inlet pipe and a hose pipe together can fill the pond in 10 hours.

The inlet pipe alone can fill the pond in one hour less time than the hose pipe can  fill the pond.

Let the hose pipe can complete the job in x hours.

Then the inlet pipe can fill the pond in (x-1) hours.

The rate of filling of hose pipe is =\frac{1}{x}

The rate of filling of inlet pipe is =\frac{1}{x-1}

The rate of filling of both pipes is = \frac 1{10}

According to the problem,

\frac{1}{x}+\frac{1}{x-1}=\frac{1}{10}

\Rightarrow \frac{x-1+x}{x(x-1)}=\frac1{10}                              [ simplifying the fraction]

\Rightarrow \frac{2x-1}{x^2-x}=\frac1{10}                            

\Rightarrow 10(2x-1)= x^2-x                [ Multiplying 10(x²-x) both sides]

\Rightarrow x^2-x= 20x-10

\Rightarrow x^2-x-20x+10=0             [ simplifying ]

\Rightarrow x^2-21x+10=0

\Rightarrow x=\frac{-(-21)\pm\sqrt{(-21)^2-4.1.10}}{2.1}       [ applying quadratic formula]

\Rightarrow x=\frac{21\pm21.93}{2.1}

⇒ x= 21.465,  -0.465

x= - 0.465 does not possible, since time can not be negative.

∴x=21.465

The hose pipe can fill the pond in 21.465 hours.

The inlet pipe can fill the pond in (21.465-1)=20.465 hours.

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4 years ago
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