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Anvisha [2.4K]
1 year ago
14

Refer to the data in the table below to answer the question. (Express percents to the nearest tenth.) You will use some of the a

nswers given more than once.
Date Description Amount Balance
2/16 Deposit $1006.28 $1049.52
2/17 Gasoline $54.92 $ 994.60
2/18 Groceries $33.45 $ 961.15
2/20 Insurance $359.65 $ 601.50
2/21 Pharmacy $51.35 $ 550.15
2/21 Burger $5.50 $ 544.65
2/22 Clothes $64.95 $ 479.70
2/23 Cash $80.00 $ 399.70
2/24 Groceries $34.92 $ 364.78
2/28 Movie $15.73 $ 349.05
3/3 Monthly rent $204.92 $ 144.13
3/5 Groceries $28.56 $ 115.57
3/16 Deposit $1006.28 $1121.85
3/18 Car maintenance $173.28 $ 948.57
Mr. Thompson, a retiree, looks at his check register. What is Mr. Thompson's yearly rent (using 12 months)? $

What was the average grocery expense in this time period? $

Knowing that he buys groceries weekly, Mr. Thompson estimates his yearly expense for groceries to be (4*12* $
) or $
.

Then, Mr. Thompson realizes there are more than 48 weeks in a year. He revises his estimate using (52 x $
) to get $
for his estimate.

Based on the calculations above, how much money should Mr. Thompson budget annually for food and rent? $

If Mr. Thompson receives $1,006.28 twelve (12) times a year, what is his yearly income? $

Expressed as a percent of income, enter an estimate for rent (to the nearest tenth) and food expenses. Rent:
%; Food:
%
Mathematics
1 answer:
AnnZ [28]1 year ago
4 0

Answer:Ask your teacher for help!

Step-by-step explanation:

Learn your math and pay attention then you’d know!

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malfutka [58]
The answer is to this is b
6 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Crm%20%5Cint_%7B0%7D%5E%20%5Cinfty%20%20%5Cfrac%7B%20%5Csqrt%5B%20%20%5Cscriptsize%5Cphi%
Rasek [7]

With ϕ ≈ 1.61803 the golden ratio, we have 1/ϕ = ϕ - 1, so that

I = \displaystyle \int_0^\infty \frac{\sqrt[\phi]{x} \tan^{-1}(x)}{(1+x^\phi)^2} \, dx = \int_0^\infty \frac{x^{\phi-1} \tan^{-1}(x)}{x (1+x^\phi)^2} \, dx

Replace x \to x^{\frac1\phi} = x^{\phi-1} :

I = \displaystyle \frac1\phi \int_0^\infty \frac{\tan^{-1}(x^{\phi-1})}{(1+x)^2} \, dx

Split the integral at x = 1. For the integral over [1, ∞), substitute x \to \frac1x :

\displaystyle \int_1^\infty \frac{\tan^{-1}(x^{\phi-1})}{(1+x)^2} \, dx = \int_0^1 \frac{\tan^{-1}(x^{1-\phi})}{\left(1+\frac1x\right)^2} \frac{dx}{x^2} = \int_0^1 \frac{\pi2 - \tan^{-1}(x^{\phi-1})}{(1+x)^2} \, dx

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8 0
2 years ago
6C + 47M=893.50<br> 25C + 22M=527.86
Olenka [21]

Answer:

C = 4.94   M = 18.38

Step-by-step explanation:

the easiest way is to graph both equaitons and see where they intersect,

see the image

or solve by substitution

6C + 47M=893.50           C = (893.50 - 47M)/6

25C + 22M=527.86

25((893.50 - 47M)/6)  + 22M = 527.86

25/6 [(893.50) - 47M] + 22M = 527.86

25/6 [ - 47M] + 22M = 527.86 - 25/6 [(893.50)

22M - 25(47M)/6  = -3195.06

22M - 195.83M  = -3195.06

      -173.83M   =   -3195.06

                 M  =  18.38

C = (893.50 - 47(18.38)/6

C = 4.94

6 0
3 years ago
Log20 log15-log12 log5
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What is this exactly?
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dimaraw [331]

Answer:

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Step-by-step explanation:

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