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1 year ago

Translate the sentence into an equation.

Mathematics

1 answer:

andrew11 [14]1 year ago

6 0

Answer:

8 x b + 9 = 7

Step-by-step explanation:

sum is to add and 8 times means to multiply it by 8

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8. Find the values of angles x, y,

Eddi Din [679]

Answer:

option A

Step-by-step explanation:

option A is the correct answer of this question.

plz mark my answer as brainlist plzzzz.

hope this will be helpful to you 

8 0

3 years ago

Read 2 more answers

1. 4x + 3(x-9) = 19

Dmitry_Shevchenko [17]

1) 4x + 3(x-9) = 19

or, 4x + 3x - 27 = 19

or, 7x = 19+27

or, 7x = 46

or, x = 46/7

◆ x = 6.57

2) 2(x-4) + 5x = 3

or, 2x - 8 + 5x = 3

or, 7x = 3+8

or, x = 11/7

◆ x = 1.57

3) 60 = 8y - 3(y-10)

or, 60 = 8y - 3y + 30

or, 60 - 30 = 5y

or, y = 30/5

◆ y = 6

4) 40 + 3c = 3 + 9(c-2)

or, 40 + 3c = 3 + 9c - 18

or, 40 + 3c = 9c - 15

or, 9c - 3c = 40 + 15

or, 6c = 55

◆ c = 9.166

I hope you understand..

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5 0

2 years ago

Read 2 more answers

What is the value of x enter your answer in the box x=

lions [1.4K]

Answer:

x = (3√34 + 1)/5 units

Step-by-step explanation:

Let's solve for x, using the Pythagorean theorem, this way:

BC is the Hypotenuse of the triangle ABC

BC² = 15² + 9²

BC² = 225 + 81

BC² = 306

BC = √9 * 34

BC = 3 √34

Now, we can substitute and solve for x, this way:

BC = 3x + 2x - 1

3 √34 = 3x + 2x - 1

3√ 34 + 1 = 5x

x = (3√34 + 1)/5 units

3 0

3 years ago

If cos() = − 2 3 and is in Quadrant III, find tan() cot() + csc(). Incorrect: Your answer is incorrect.

nydimaria [60]

Answer:

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \frac{5 - 3\sqrt 5}{5}$

Step-by-step explanation:

Given

$\cos(\theta) = -\frac{2}{3}$

$\theta \to$ Quadrant III

Required

Determine $\tan(\theta) \cdot \cot(\theta) + \csc(\theta)$

We have:

$\cos(\theta) = -\frac{2}{3}$

We know that:

$\sin^2(\theta) + \cos^2(\theta) = 1$

This gives:

$\sin^2(\theta) + (-\frac{2}{3})^2 = 1$

$\sin^2(\theta) + (\frac{4}{9}) = 1$

Collect like terms

$\sin^2(\theta) = 1 - \frac{4}{9}$

Take LCM and solve

$\sin^2(\theta) = \frac{9 -4}{9}$

$\sin^2(\theta) = \frac{5}{9}$

Take the square roots of both sides

$\sin(\theta) = \±\frac{\sqrt 5}{3}$

Sin is negative in quadrant III. So:

$\sin(\theta) = -\frac{\sqrt 5}{3}$

Calculate $\csc(\theta)$

$\csc(\theta) = \frac{1}{\sin(\theta)}$

We have: $\sin(\theta) = -\frac{\sqrt 5}{3}$

So:

$\csc(\theta) = \frac{1}{-\frac{\sqrt 5}{3}}$

$\csc(\theta) = \frac{-3}{\sqrt 5}$

Rationalize

$\csc(\theta) = \frac{-3}{\sqrt 5}*\frac{\sqrt 5}{\sqrt 5}$

$\csc(\theta) = \frac{-3\sqrt 5}{5}$

So, we have:

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta)$

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \tan(\theta) \cdot \frac{1}{\tan(\theta)} + \csc(\theta)$

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = 1 + \csc(\theta)$

Substitute: $\csc(\theta) = \frac{-3\sqrt 5}{5}$

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = 1 -\frac{3\sqrt 5}{5}$

Take LCM

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \frac{5 - 3\sqrt 5}{5}$

6 0

3 years ago

Fill in the blank so that the ordered pair is a solution of y=12x+2. ( , 14)

marusya05 [52]

Answer:

x=1

Step-by-step explanation:

14=12x+2

subtract 2 from both sides

12=12x

divide both sides by 12 and you get x=1

8 0

4 years ago