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kondaur [170]
1 year ago
6

The weights, in pounds, for 15 horses in a stable were

Mathematics
1 answer:
sweet-ann [11.9K]1 year ago
7 0

The median value remains unchanged if the four values are reported using the corrected weight.

The correct answer is an option (B)

We know that the mean is calculated by finding the sum of all the weights of the horses and then dividing by the number of horses.

Decreasing one of the weights would decrease the sum and therefore decrease the mean.

So, the choice A is incorrect.

We know that the range is the difference between the highest and lowest weights, so decreasing the lowest weight would increase the range.

So, the choice C is incorrect.

We know that the Standard deviation is calculated based on the mean weight of the horses.

And decreasing one of the weights decreases the mean and therefore would affect the standard deviation.

So, the choice D is incorrect.

Now, as we know the median the middle value in a sorted, ascending or descending list of values.

So, the median weight is found by ordering the horses’ weights from least to greatest and then determining the middle value from this list of weights.

Decreasing the value for the horse with the lowest weight doesn’t affect the median since it’s still the lowest value.

Therefore, the median value remains unchanged if the four values are reported using the corrected weight.

The correct answer is an option (B)

Learn more about the median here:

brainly.com/question/28060453

#SPJ4

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Can someone please help me and explain if you can
nadezda [96]

Answer:

∠6=116°

Step-by-step explanation:

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  • We are given the values of ∠4 (-2x+94) and ∠8 (-5x+139).
  • Vertical angles are congruent. Angle 4 and angle 1 are vertical angles, so angle 1 is also -2x+94.
  • ∠1 and ∠8 are alternate exterior angles. The transversal is the line that crosses over the parallel lines. When two angles are on opposite sides of the transversal, they are alternate angles. When the two angles are on the outside of the parallel lines, they are exterior angles. This makes them alternate-exterior angles.
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-2x+94=-5x+139

Solve for x. Subtract 94 from both sides:

-2x+94-94=-5x+139-94\\\\-2x=-5x+45

Add 5x to both sides:

-2x+5x=-5x+5x+45\\\\3x=45

Divide both sides by 3:

\frac{3x}{3} =\frac{45}{3} \\\\x=15

Insert the value of x into angle 4 because they are same-side interior angles. This is because they are on the same side of the transversal and within the parallel lines. Same-side interior angles are supplementary, so their value will add up to 180°. Therefore, in order to find angle 6, we need to first find the true value of angle 4:

x=15\\\\-2(15)+94\\\\-30+94\\\\64

∠4 is 64°. Use ∠a+∠b=180 to find angle 6:

a+64=180

a represents angle 6. Subtract 64 from both sides:

a+64-64=180-64\\\\a=116

Angle 6 has a measure of 116°.

:Done

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