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kondaur [170]
2 years ago
6

The weights, in pounds, for 15 horses in a stable were

Mathematics
1 answer:
sweet-ann [11.9K]2 years ago
7 0

The median value remains unchanged if the four values are reported using the corrected weight.

The correct answer is an option (B)

We know that the mean is calculated by finding the sum of all the weights of the horses and then dividing by the number of horses.

Decreasing one of the weights would decrease the sum and therefore decrease the mean.

So, the choice A is incorrect.

We know that the range is the difference between the highest and lowest weights, so decreasing the lowest weight would increase the range.

So, the choice C is incorrect.

We know that the Standard deviation is calculated based on the mean weight of the horses.

And decreasing one of the weights decreases the mean and therefore would affect the standard deviation.

So, the choice D is incorrect.

Now, as we know the median the middle value in a sorted, ascending or descending list of values.

So, the median weight is found by ordering the horses’ weights from least to greatest and then determining the middle value from this list of weights.

Decreasing the value for the horse with the lowest weight doesn’t affect the median since it’s still the lowest value.

Therefore, the median value remains unchanged if the four values are reported using the corrected weight.

The correct answer is an option (B)

Learn more about the median here:

brainly.com/question/28060453

#SPJ4

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In the formula A(t) = A0ekt, A(t) is the amount of radioactive material remaining from an initial amount A0 at a given time t an
Alenkasestr [34]

Answer:  693 years

Step-by-step explanation:

Expression for rate law for first order kinetics is given by:

A(t) =A_0e^{kt}

k = rate constant

t = time taken for decomposition = 1

A_0 = Initial amount of the reactant

A_t = amount of the reactant left =A_0-\frac{0.1}{100}\times A_0=0.999A_0

0.999A_0=A_0e^{k\times 1}

0.999=e^k

k=-0.001year^{-1}

for half life : t=t_\frac{1}{2}

A_t=\frac{1}{2}A_o

Putting in the values , we get

\frac{1}{2}A_0=A_0e^{-0.001\times t_\frac{1}{2}

t_\frac{1}{2}=693 years

Thus half life of this isotope, to the nearest year is 693.

8 0
3 years ago
PLZ HELP I WILL GIVE BRAINLIEST
Kipish [7]

Answer:

the third one

Step-by-step explanation:

bc like there are 2 boxes of 1 and 5 boxes of 1/6 so thats already 2 and 5/6 which applies to all of them. then there is 1 box of 1 and 2 boxes of 1/3 so thats 1 and 1/3 which applies to all of them also but when you make them have the same denominator you get 2 and 5/6 + 1 and 4/6 which deletes the second one. When you add you should get the same denominator so that deletes the first one so then you simplify that and the fraction should still be equal to the unsimplified fraction so you should get 4 and 1/2 if that makes sense

8 0
3 years ago
What is the slope intercept form of the line that passes through the point (-2,-18) and has a slope of 1/4
mart [117]

Answer:

y=(1/4)x - 35/2

Step-by-step explanation:

y=mx+b

y=(x/4)+b                 plug in the slope (m)

-18=(-2/4)+b             plug in x and y

b= -17 1/2= -35/2     solve for b

y=(1/4)x - 35/2         plug in m and b into the equation

8 0
3 years ago
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vodomira [7]

Step-by-step explanation:

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5 0
3 years ago
6m+4=8m then 4 m. What is the answer
tekilochka [14]

6m+4 = 8m

8m-6m = 4

2m = 4

m = 2

if you are asking for 4m, then it would be 4(2) = 8

5 0
4 years ago
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