All categories

1 year ago

Please help I’m being timed

Mathematics

2 answers:

umka2103 [35]1 year ago

6 0

Answer:

ADF

Step-by-step explanation:

Three points are said to be collinear if they lie on the same straight line and non-collinear if not. Only AD and F are not on the same straight line. So they are non-collinear

olganol [36]1 year ago

3 0

Answer:

F.B.G

Step-by-step explanation:

Ive done this before, quite simple actually

You might be interested in

I need help eeeeeeeeeeeeeeeeee

sattari [20]

Answer:

i havent did this in years BUt i will try the top would be the same as the bottom

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Pls help I’ll brainlest

Elanso [62]

Answer:

It would be B.

Step-by-step explanation:

This is because adding a negative exponent onto a number is telling you how many times you have to divide it by. So in this case, it would be the equation 1 / 2^4 to solve it.

5 0

3 years ago

Read 2 more answers

Factor completely.

riadik2000 [5.3K]

25a⁴ - 10a²z² - 8z⁴ multiply 25*-8 = -200 to find factors (10*-20 = 200), (10 - 20 = -10)

25a⁴ + 10a²z² - 20a²z² - 8z⁴ factor the left two and right two terms

5a²(5a² + 2z²) -4z²(5a² + 2z²) one factor from each side should be identical

= (5a² - 4z²)(5a² + 2z²)

7 0

3 years ago

I need help asap!! please!!

andre [41]

Wouldnt it be a dot on the line right in between 75 and 76 pointing towards the left? im not sure

4 0

4 years ago

Read 2 more answers

A 10 ft ladder is being pulled away from a wall at a rate of 3 ft/sec. What is the rate of change in the area beneath the ladder

andriy [413]

Answer:

The rate of change in the area beneath the ladder is 5.25 ft²/s

Step-by-step explanation:

Area of triangle is given by;

$A = \frac{1}{2}bh\\\\2A = bh\\\\take \ derivative \ of \ both \ sides \ with \ respect \ to \ "t"\\\\2\frac{dA}{dt} = h\frac{db}{dt} + b\frac{dh}{dt}\\\\divide \ through \ by \ 2\\\\\frac{dA}{dt} = (\frac{h}{2} )\frac{db}{dt} + (\frac{b}{2}) \frac{dh}{dt}$

where;

b is the base of the triangle, given as 6 ft

h is the height of the triangle, determined by applying Pythagoras theorem.

h² = 10² - 6²

h² = 100 - 36

h² = 64

h = √64

h = 8 ft

Determine the rate of change of the height;

$h^2 + b^2 = 10^2\\\\h^2 + b^2 =100\\\\2h\frac{dh}{dt} + 2b\frac{db}{dt} =0\\\\h\frac{dh}{dt} + b\frac{db}{dt} =0\\\\h \frac{dh}{dt} = -b\frac{db}{dt} \\\\\frac{dh}{dt} = (\frac{-b}{h} )\frac{db}{dt}\\\\\frac{dh}{dt} =(\frac{-6}{8})(3)\\\\\frac{dh}{dt} = -\frac{9}{4} \ ft/s$

Finally, determine the rate of change of area beneath the ladder;

$\frac{dA}{dt} = (\frac{h}{2} )\frac{db}{dt} + (\frac{b}{2}) \frac{dh}{dt}\\\\\frac{dA}{dt} = (\frac{8}{2} )(3) + (\frac{6}{2}) (\frac{-9}{4})\\\\\frac{dA}{dt} = 12 - \frac{27}{4} \\\\\frac{dA}{dt} = \frac{48-27}{4}\\\\\frac{dA}{dt} = \frac{21}{4} \ ft^2/s\\\\\frac{dA}{dt} = 5.25 \ ft^2/s$

Therefore, the rate of change in the area beneath the ladder is 5.25 ft²/s

5 0

3 years ago