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STatiana [176]
2 years ago
11

Which type of friction acts on an object that is not moving?

Geography
1 answer:
aivan3 [116]2 years ago
4 0

The type of friction that acts on an object that is not moving is option A, static friction.

<h3>What is static friction?</h3>

Static friction serves as a kind of friction that do occur between two object that are not moving which means the object are static in nature.

In this case, The type of friction that acts on an object that is not moving is static friction.

Learn more aboutstatic friction on:

brainly.com/question/13680415

#SPJ1

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Answer:

1) a) r_{R,I} = 1150\,m, b) r_{R,II} = 3400\,m, c) r_{R,III} = 2750\,m.

2) a) r_{R,I} = 45,2\,km, b) r_{R, II} = 28,15\,km, c) r_{R,III} = 51,8\,km.

Explanation:

The scale factor is defined by the following expression:

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r_{S} - Scale distance, in centimetres.

r_{R} - Real distance, in centimetres.

1) If we know that n = \frac{1}{50000}, r_{S,I} = 2,3\,cm, r_{S,II} = 6,8\,cm and r_{S,III} = 5,5\,cm, then the actual distances in metres are:

r_{R,I} = \frac{r_{S,I}}{n}

r_{R,I} = \frac{2,3\,cm}{\frac{1}{50000} }

r_{R,I} = 115000\,cm

r_{R,I} = 1150\,m

r_{R,II} = \frac{r_{S,II}}{n}

r_{R,II} = \frac{6,8\,cm}{\frac{1}{50000} }

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r_{R, III} = \frac{r_{S, III}}{n}

r_{R,III} = \frac{5,5\,cm}{\frac{1}{50000} }

r_{R,III} = 275000\,cm

r_{R,III} = 2750\,m

2) If we know that n = \frac{1}{50000}, r_{S, I} = 90,4\,cm, r_{S, II} = 56,3\,cm and r_{S,III} = 103,6\,cm, then the actual distance in kilometres is:

r_{R,I} = \frac{r_{S,I}}{n}

r_{R,I} = \frac{90,4\,cm}{\frac{1}{50000} }

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r_{R,I} = 45,2\,km

r_{R,II} = \frac{r_{S,II}}{n}

r_{R,II} = \frac{56,3\,cm}{\frac{1}{50000} }

r_{R,II} = 2815000\,cm

r_{R, II} = 28,15\,km

r_{R, III} = \frac{r_{S, III}}{n}

r_{R,III} = \frac{103,6\,cm}{\frac{1}{50000} }

r_{R,III} = 5180000\,cm

r_{R,III} = 51,8\,km

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