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Tema [17]
1 year ago
7

Find an equation of the horizontal line passing through the point (5, -2).

Mathematics
2 answers:
erma4kov [3.2K]1 year ago
6 0

Answer:

y=-2

Step-by-step explanation:

easy

Elis [28]1 year ago
4 0
<h3>Answer:   y = -2</h3>

Explanation:

The horizontal line through (5, -2) will have all y coordinates be the same. So that's how we get to y = -2

Other points on this horizontal line are:

(1, -2)

(2, -2)

(3, -2)

(4, -2)

etc

The slope of any horizontal flat line is 0

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Which expression is equivalent to -3 (2m - 1) - n?
Semenov [28]

Answer:

−6−m+3

Explanation

-3 (2m - 1) - n?

Distribute

−3(2−1)−

−6+3−

Rearange

−6+3−

−6−m+3

7 0
3 years ago
The population of Henderson City was 3,381,000 in 1994, and is growing at an annual rate 1.8%
liq [111]
<h2>In the year 2000, population will be 3,762,979 approximately. Population will double by the year 2033.</h2>

Step-by-step explanation:

   Given that the population grows every year at the same rate( 1.8% ), we can model the population similar to a compound Interest problem.

   From 1994, every subsequent year the new population is obtained by multiplying the previous years' population by \frac{100+1.8}{100} = \frac{101.8}{100}.

   So, the population in the year t can be given by P(t)=3,381,000\textrm{x}(\frac{101.8}{100})^{(t-1994)}

   Population in the year 2000 = 3,381,000\textrm{x}(\frac{101.8}{100})^{6}=3,762,979.38

Population in year 2000 = 3,762,979

   Let us assume population doubles by year y.

2\textrm{x}(3,381,000)=(3,381,000)\textrm{x}(\frac{101.8}{100})^{(y-1994)}

log_{10}2=(y-1994)log_{10}(\frac{101.8}{100})

y-1994=\frac{log_{10}2}{log_{10}1.018}=38.8537

y≈2033

∴ By 2033, the population doubles.

4 0
3 years ago
A zoo measured the wingspan, in millimeters of 9 butterflies What is the median length of the wingspan
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Step-by-step explanation:

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3 years ago
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