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Nostrana [21]
1 year ago
15

If both sides of a gable roof are the same size, and one side of the roof measures 15'x 36*, how many squares of 16" x 5/2" wood

en shingles will be needed to cover this roof? the shingles will be applied with a weather exposure of 5". (round your answer up to the nearest whole square.)
Mathematics
1 answer:
kogti [31]1 year ago
4 0

Approximately 3 shingles used to cove the area of the roof.

According to the statement

we have to find the number of shingles used to cover the roof.

So, For this purpose, we know that the

one side of the roof measures 15'x 36

And we have given that the both sides of a gable roof are the same size.

So, For this purpose,

The roof is a of a rectangle shape so,

Area of rectangle = 2(L+B)

Then

Area of rectangle = 2(L+B)

Area of rectangle = 2(15+36)

Area of rectangle = 102 ft.

Then

Area of shingles = 2(L+B)

Area of shingles = 2(16+2.5)

Area of shingles = 37

then number of shingles used = 37/102

So, Approximately 3 shingles used to cove the area of the roof.

Learn more about Area here

brainly.com/question/6613758

#SPJ4

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igomit [66]

Answer:

4 − 3

Step-by-step explanation:

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Kate divides 1/2 gallon of water equally among 5 plants.
elixir [45]

Answer: It would be 1/2 divided by 5. In other words 1/2 times 1/5. That equals 1/10. Each plant would get 1/10 of a gallon each. To check you would multiply 1/10 times 5.<em> </em><em>That equals</em><em> </em><u><em>1/2</em></u>

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2 years ago
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What is the limit of f (×) as x approaches - infinty
tatyana61 [14]
If the degree of numerator and denominator are equal, then limit will be leading coefficient of numerator divided by the leading coefficient of denominator.

So then the limit would be 3/1 = 3.

Alternatively,

\displaystyle \lim_{x\to\infty}\dfrac{3x^2+6}{x^2-4}=\displaystyle \lim_{x\to\infty}\dfrac{3x^2+6}{x^2-4}\cdot\dfrac{1/x^2}{1/x^2}=\lim_{x\to\infty}\dfrac{3+\frac6{x^2}}{1-\frac4{x^2}} = \dfrac{3+0}{1-0}=\boxed{3}

Hope this helps.
5 0
3 years ago
How do I solve 7√96m^3 ?
aksik [14]
I BELIEVE THAT ALL (96m^3) IS UNDER THE SQUARE ROOT.
If so : 96 could be written as 16x 6 & m³ could be written as m²xm:

7√(96m^3) = 7√(16 x 6 x m² m) =7[4m√(6m)]

=28m√(6m)
4 0
2 years ago
Read 2 more answers
Solve and verify please solve​
RUDIKE [14]

Answer:

Below in bold.

Step-by-step explanation:

I'll solve a few of them to illustrate the method:

a) 5x - (3x - 1) = x - 4

The aim is to get all the 'x' terms to one sides of the '=' and the numbers to the other side:

Distribute the negative over the 3x - 1 in the parentheses:

5x - 3x + 1 = x - 4        ( Note that  -* -1 = + 1)

Now subtract  1 from both sides:

5x - 3x + 1 - 1 = x - 4 - 1

5x - 3x = x - 5

Now subtract x from both sides:

5x - 3x - x = x - x - 5.

2x - x = -5

x = -5.

(b) 3/5 x + 1 = 2/5 - 3x

We first get rid of the fractions by multiplying each term by 5:

5 * 3/5 x + 1*5 = 5 * 2/5 - 5*3x

3x + 5 = 2 - 15x

3x + 15x + 5 = 2 - 15x + 15x        (adding 15x to both sides)

18x + 5 = 2          Subtract 5 from both sides:

18x + 5 - 5 = 2 - 5

18x = -3

Now we divide both sides by 18:

x = -3/18 = -1/6.

g) 0.3(6 + m) = 0.4(8 - m)

0.3 * 6 + 0.3* m = 0.4*8 + 0.4 * -m   ( Distributing the 0.3 and 0.4 over the parentheses)

1.8 + 0.3m = 3.2 - 0.4m        ( recall that + * - = -)

1.8 - 1.8 + 0.3m = 3.2 - 1.8 - 0.4m

0.3m = 1.4 - 0.4m

0.3m + 0.4m = 1.4 - 0.4m + 0.4m

0.7m = 1.4

m = 1/4/0.7

m =  2.

I hope this helps.

5 0
3 years ago
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