Answer:
B. y = -2/3x + 12
Step-by-step explanation:
Formula to find the slope when given two points on a line:
<u>y</u><u>2</u><u> </u><u>-</u><u> </u><u>y</u><u>1</u>
x2 - x1
Substitute the two given points (6, 8) (9, 6):
<u>6</u><u> </u><u>-</u><u> </u><u>8</u>
9 - 6
Slope = -2/3x
We found the slope! And the answer choices already gave us one y-intercept, which is 12. The last thing we do is we form an equation with the information we solved and that was given to us.
y = slope (x) + y-intercept
y = -2/3x + 12
The answer choice that matches this equation is B.
In conclusion, the equation that best estimates the line of best fit shown above is answer choice B.
Answer:
f(3x) - 2g(x+1) = 12x - 5
Step-by-step explanation:
You've got f[g(x)] and g[f(x)] correct
However, f(3x) means substitute 3x for x in f(x):
f(3x) = 2(3x) - 3
⇒ f(3x) = 6x - 3
2g(x+1) = 2[4 - 3(x + 1)]
⇒ 2g(x+1) = 2[4 - 3x -3]
⇒ 2g(x+1) = 2[1 - 3x]
⇒ 2g(x+1) = 2 - 6x
f(3x) - 2g(x+1) = (6x - 3) - (2 - 6x)
⇒ f(3x) - 2g(x+1) = 12x - 5
Answer:
5/4 cups of flour
Step-by-step explanation:
3/4+1/2 = 1 1/4 or 5/4
Answer:
13 hours
Step-by-step explanation:
Average speed = Distance traveled / time taken
⇒ Distance = Average speed × Time
d = s × t
For the first trip;
Average speed = 280 mph
d₁ = 280t₁ ------(1)
where;
d₁ is the distance covered to get to the destination
t₁ is the time taken to get to the destination
For the second trip;
Average speed = 240 mph
d₂= 240t₂ ------(2)
where;
d₂ is the distance covered on the way back
t₂ is the time taken on the way back
The trip is the same distance to and fro. Therefore,
d₁ = d₂
Substituting the equation for d₁ and d₂
280t₁ = 240t₂ ------(3)
It took one hour less time to get there than it did to get back, then,
t₁ = t₂ - 1
t₂ = t₁ + 1 ------(4)
Substituting equation (4) into equation (3)
280t₁ = 240(t₁ + 1)
280t₁ = 240t₁ + 240
280t₁ - 240t₁ = 240
40t₁ = 240
t₁ = 240/40
t₁ = 6 hours
From equation (4)
t₂ = t₁ + 1
t₂ = 6 + 1
t₂ = 7 hours
The total time for the trip is t₁ + t₂ = 6 + 7
= 13 hours
I believe your answer is D. 77.
