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tatyana61 [14]
2 years ago
6

PLEASE HELP I REALLY NEED IT!!!! WORTH 100 POINTS

Mathematics
1 answer:
-Dominant- [34]2 years ago
3 0

Answer:

Question 1 : The answer is 143.3 miles

Question 2 : The answer is 120 minutes

Step-by-step explanation:

1.Based on the give conditions:

43 \times 90 \div 27 \\ calculate \frac{43 \times 90}{27}  =  \frac{430}{3}= 143.3

2. 90 miles = 75min

143.3 ÷ 90 = 1.6

75 × 1.6 = 120

so the answer is 120 min

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The following values represent the amount of money (in dollars) 10 people have in their wallets: 10, 12, 19, 5, 6, 8, 1, 13, 4,
boyakko [2]

The median of all these numbers in dollars is 7.5.

<h3>How to obtain median when no. of given data are odd ?</h3>

When the no. of given data are odd we arrange those nos. in an order increasing or decreasing order and the middle no. is the median of the given odd numbers.

According to the given question the following values represent the amount of money (in dollars) 10 people have in their wallets: 10, 12, 19, 5, 6, 8, 1, 13, 4, 7 and we have to find the median.

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Now lets arrange these nos. in an order from least to greatest which is

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2 years ago
Write the coordinates of the vertices after a reflection over the y-axis.
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Answer:

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K' : (5, 1)

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Answer:

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Step-by-step explanation:

\cos\alpha=\dfrac{63}{65}\\\\\text{use}\ \sin^2\alpha+\cos^2\alpha=1\\\\\sin^2\alpha+\left(\dfrac{63}{65}\right)^2=1\\\\\sin^2\alpha+\dfrac{3969}{4225}=1\qquad\text{subtract}\ \dfrac{3969}{4225}\ \text{from both sides}\\\\\sin^2\alpha=\dfrac{4225}{4225}-\dfrac{3969}{4225}\\\\\sin^2\alpha=\dfrac{256}{4225}\to\sin\alpha=\pm\sqrt{\dfrac{256}{4225}}\\\\\sin\alpha=\pm\dfrac{\sqrt{256}}{\sqrt{4225}}\\\\\sin\alpha=\pm\dfrac{16}{65}

\text{use}\ \tan\alpha=\dfrac{\sin\alpha}{\cos\alpha}\\\\\text{substitute:}\\\\\tan\alpha=\dfrac{\pm\frac{16}{65}}{\frac{63}{65}}=\pm\dfrac{16}{65}\cdot\dfrac{65}{63}=\pm\dfrac{16}{63}

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