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kodGreya [7K]
2 years ago
12

A(6-1) , В(2,3) help pls

Mathematics
1 answer:
bulgar [2K]2 years ago
6 0
Use x and y coordinate separately for distance.

Sqrt{ (6-2)^2 + (-1-3)^2 }
Sqrt(32)

4sqrt(2)
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This measures the deviation between the scores and the mean; it measures how dispersed the data is. The higher this is the more
Llana [10]

D.standard deviation

4 0
3 years ago
F(x) = – x3 + 5x2 + 6x + 1 find the degree
Arte-miy333 [17]

To find the degree of this function, you would look at the first term of the function, which is 3. So, the degree of this function would be 3.

3 0
3 years ago
Please help ASAP!!!!!!!
VLD [36.1K]

Answer:

10th term is 10

Step-by-step explanation:

The nth term for finding the geometric progression is expressed as;

Tn = ar^n-1

a is the first term

r is the common ratio

n is the number of terms

a11 = ar^11-1

a11 = ar^10

Since a11 = -5 and r = -1/2

-5 = a(-1/2)^10

-5 = a(1/1024)

a= 1024 * -5

a = -5120

Nest is to get the 10th terms

a10 = ar^9

a10 = -5120 * (-1/2)^9

a10 = -5120 * -1/512

a10 = 10

Hence the 10th term of the sequence is 10

3 0
3 years ago
4y = 42 - 3y<br><br> Can you help me find y?
Lesechka [4]
4y = 42 - 3y

First, add '3y' to both of the sides.
4y + 3y = 42
Second, add '4y + 3y' to get '7y'.
7y = 42
Third, divide both sides by '7'.
y =  \frac{42}{7}
Fourth, how many times does 7 go into 42? 42 ÷ 7 = '6'.
y = 6

Answer: y = 6

7 0
3 years ago
Read 2 more answers
Rewrite 5√4 * √2 as a single radical.
melisa1 [442]

Answer:

the 2nd

Step-by-step explanation:

\sqrt[5]{4}   \times  \sqrt{2 }  \\  {4}^{ \frac{1}{5} }   \times   {2}^{ \frac{1}{2} }  \\  {2}^{2 \times \frac{1}{5}  }  \times  {2}^{ \frac{1}{2} }  \\  {2}^{ \frac{2}{5}  +  \frac{1}{2} }  \\   {2}^{ \frac{9}{10} }  =  \sqrt[10]{ {2}^{9} }

8 0
3 years ago
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