Question

On the graph of f(x)=sinx and the domain 2π≤x<4π, for which of the following intervals is f(x) strictly increasing?

Answer 1

Using equivalent angles, on the domain 2π≤x<4π, f(x) = sin(x) is increasing for:

• 2π < x < 5π/2.

• 7π/2 < x < 4π.

What are equivalent angles?

Each angle on the second, third and fourth quadrants will have an equivalent on the first quadrant.

This is also true for each lap of the circle, as the first lap is in the interval 0 < x < 2π. On the first lap, the increasing intervals are:

• 0 < x < π/2.

• 3π/2 < x < 2π.

On the second lap, to find the equivalent angles, we add 2π, hence the intervals is:

• 2π < x < 5π/2.

• 7π/2 < x < 4π.

More can be learned about equivalent angles at brainly.com/question/24787111

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