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sleet_krkn [62]
2 years ago
10

What do i write for this and what do i draw??

Mathematics
1 answer:
Klio2033 [76]2 years ago
6 0

The centre of the rotation is A

The line of the reflection is Y

Vertex A of the triangle ABC when rotated by 90° counterclockwise about the origin,

Rule to be followed,

A(x, y) → P(-y, x)

Therefore, A(1, 1) → P(-1, 1)

Similarly, B(3, 2) → Q(-2, 3)

C(2, 5) → R(-5, 2)

Triangle given in second quadrant will be the triangle PQR.

If the point P of triangle PQR is reflected across a line y = x,

Rule to be followed,

P(x, y) → X(y, x)

P(-1, 1) → X(1, -1)

Similarly, Q(-2, 3) → Y(3, -2)

R(-5, 2) → Z(2, -5)

Therefore, triangle given in the fourth quadrant is triangle XYZ.

Learn more about reflection

brainly.com/question/13805069

#SPJ9

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Answer:

7/25

Step-by-step explanation:

because its .28

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Is anyone able to solve this system of equation? ​
kkurt [141]

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Step-by-step explanation:

see photo attached for further explanation...

7 0
3 years ago
The base of the prism in the diagram is rectangular, but the edges that are not parallel to the base are tilted. What is the vol
Aneli [31]

Answer:

Volume of the prism is 648cm^3

Step-by-step explanation:

Given:

Base of the prism is rectangular in shape

Height of the prism = 6 cm

Base length of the prism= 12 cm

Base width of the prism= 9 cm

To Find:

Volume of the prism=?

Solution:

Volume of the prism ,

V= Base area of the prism x  Height of the prism

Here in the figure  base of the prism is in  Rectangular form

So the base area of the prism = area of the rectangle

We know that the area of the rectangle is = length x height

Substituting the values

Area of the Rectangle = 12 x 9

Area of the Rectangle = 108

So  the are of the base of the prism is  108cm^2

Now

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V= 108 X 6

V= 648cm^3

7 0
3 years ago
It is possible to score higher than 1600 on the combined mathematics and reading portions of the SAT, but scores 1600 and above
Citrus2011 [14]

Answer:

The proportion of scores reported as 1600 is 0.0032

Step-by-step explanation:

Let X be the score for 1 random person in SAT combining maths and reading. X has distribution approximately N(μ = 1011,σ = 216).

In order to make computations, we standarize X to obtain a random variable W with distribution approximately N(0,1)

W = \frac{X-\mu}{\sigma} = \frac{X-1011}{216} \simeq N(0,1)

The values of the cummulative distribution function of the standard Normal random variable, lets denote it \phi are tabulated, you can find those values in the attached file. Now, we are ready to compute the probability of X being bigger than 1600

P(1600< X) = P(\frac{1600-1011}{216} < \frac{X-1011}{216}) = P(2.7269 < W) = 1- \phi(2.7269)\\= 1- 0.9968 = 0.0032

Hence, the proportion of scores reported as 1600 is 0.0032.

Download pdf
5 0
4 years ago
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