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arlik [135]
2 years ago
9

On the back of Jack's monthly statement, he listed the following outstanding withdrawals # 123, $67.09 , #117, $300, #130, $280.

25, debit card, $430.50,
and #138, $38.71. He also determined that a deposit for $400 and another for $238.90 are outstanding Using these outstanding transactions, what
adjustment will have to be made to his statement balance?

A. -$631.62
B. -$1116.55
C. $1955.45
D. -$277.90
Mathematics
1 answer:
Ede4ka [16]2 years ago
7 0

The adjustment that will be made to Jack's statement balance is <u>B. -$1116.55</u>.

<h3>What is bank reconciliation?</h3>

Bank reconciliation is the process of making the records kept by an account holder agree with the records maintained by the bank.

Bank reconciliation is carried out by reviewing the differences between the two records and recording adjustments.

<h3>Data and Calculations:</h3><h3>Outstanding withdrawals:</h3>

#123,             $67.09

#117,            $300

#130,           $280.25

Debit card, $430.50,

#138,              $38.71.

Total outstanding withdrawals = $1,116.55

<h3>Outstanding deposits:</h3>

Deposit $400

Deposit $238.90

Total outstanding deposits = $638.90

Thus, the adjustment that will be made to Jack's statement balance is <u>B. -$1116.55</u>.

Learn more about bank reconciliations at brainly.com/question/15525383

#SPJ1

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-1 5/6x 6 1/2<br> please explain now!
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The value of the given expression -1 5/6 x 6 1/2 is equal to  -11 11/12.

As given in the question,

Given expression is equal to :

-1 5/6 x 6 1/2

Simplify the given expression -1 5/6 x 6 1/2 to get the value of the expression:

-1 5/6 x 6 1/2

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Therefore, the value of the given expression -1 5/6 x 6 1/2 is equal to  -11 11/12.

The complete question is:

Find the value of the given expression:

-1 5/6 x 6 1/2

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8 0
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Read 2 more answers
Average sales for an online textbook distributor were $67.63 per customer per purchase. Assume the sales are normally distribute
Fynjy0 [20]

Answer:

(a)P(x>85.55)=0.02275

(b)P(x

Step-by-step explanation:

We are given that

Average sales for an online textbook distributor  per customer per purchase

,\mu=$67.63

Standard deviation of the amount spent on textbooks,\sigma=$8.96

(a) We have to find probability for a randomly selected customer spent more than $85.55 per purchase.

P(x>85.55)=P(\frac{x-\mu}{\sigma}>\frac{85.55-67.63}{8.96})

=P(Z>2)

=1-P(Z\leq 2)

=1-0.97725

P(x>85.55)=0.02275

(b)We have to find probability for a randomly selected customer spent less than $76.59 per purchase

P(x

P(x

P(x

6 0
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