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Dimas [21]
1 year ago
9

Find the lengths of nails with the following penny sizes: 3, 6, and 10. The 3-penny nail is inches. the 6 penny is__ the 3 penny

is __ the ten penny is ___
Mathematics
1 answer:
stealth61 [152]1 year ago
6 0

the lengths of nails with the following penny sizes: 3, 6, and 10

  • A 3-penny nail is_5/4_inches.
  • A 6-penny nail is_2_inches.
  • A 10-penny nail is_3_inches.

This is further explained below.

<h3>What is the lengths of nails with the following penny sizes: 3, 6, and 10?</h3>

That is the equation solved for n.

The penny size is d, and n is the length of the nail, then:

if d = 3, we have:

n = (3 + 2)/4 = 5/4

if d = 6, then

n = (6 + 2)/4 = 2

if d = 10, then:

n = (10 + 2)/4 = 3

Thus:

A 3-penny nail is_5/4_inches.

A 6-penny nail is_2_inches.

A 10-penny nail is_3_inches.

if you want to learn more about linear equations:

brainly.com/question/1884491

#SPJ1

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Step-by-step explanation:

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Step-by-step explanation:

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365 *  42.195   =  15401.175  metros

7 0
2 years ago
Enter the equation of the line in slope-intercept form. Slope is 1 3 , and (6, 3) is on the line.
Jlenok [28]

Answer:

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Step-by-step explanation:

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7 0
2 years ago
A wireless phone plan costs Eric $35 for a month of service during which he sent 450 text messages. If he was charged an fixed a
Taya2010 [7]

Answer:

5 cents

Step-by-step explanation:

Let m = cost per message

450m + 12.5 = 35    subtract 12.5 from both sides

450m = 35-12.5

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m = 22.5/450

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4 0
3 years ago
Which operation results in an expression equivalent to ? 23y^4 - 6y^3 + 35y^2 - 20y
Tom [10]

Answer:

D. P + Q

Explanation:

Given:

P = 8y⁴ + 6y³ + 8y

Q = (5y² - 4y)(3y² + 7)

Required:

Determine which operation will give an expression equivalent to 23y⁴ - 6y³ + 35y² - 20y.

SOLUTION:

Perform each operation given to see which of them gives an expression equivalent to 23y⁴ - 6y³ + 35y² - 20y.

Q - P:

P = 8y⁴ + 6y³ + 8y

Q = (5y² - 4y)(3y² + 7)

Q - P = (5y² - 4y)(3y² + 7) - (8y⁴ + 6y³ + 8y)

(5y²(3y² + 7) -4y(3y² + 7)) - (8y⁴ + 6y³ + 8y)

(15y⁴ + 35y² - 12y³ - 28y) - (8y⁴ + 6y³ + 8y)

Open parentheses

15y⁴ + 35y² - 12y³ - 28y - 8y⁴ - 6y³ - 8y

Collect like terms

15y⁴ - 8y⁴ - 12y³ - 6y³ + 35y² - 28y - 8y

7y⁴ - 18y³ + 35y² - 36y

Therefore, P - Q does not give us an expression equivalent to 23y⁴ - 6y³ + 35y² - 20y.

PQ:

P = 8y⁴ + 6y³ + 8y

Q = (5y² - 4y)(3y² + 7) = (15y⁴ + 35y² - 12y³ - 28y)

PQ = (8y⁴ + 6y³ + 8y)(15y⁴ + 35y² - 12y³ - 28y)

=(8y⁴(15y⁴ + 35y² - 12y³ - 28y) +6y³(8y⁴ + 6y³ + 8y)(15y⁴ + 35y² - 12y³ - 28y) +8y(8y⁴ + 6y³ + 8y)(15y⁴ + 35y² - 12y³ - 28y))

= 120y⁸ . . . . .

Note: You don't need to perform this operation further anymore. It would definitely not give us the equivalent expression we are looking for. The degree of the leading term (120y⁸) is way too greater than the degree of the leading term (23y⁴) of the equivalent expression we are looking for.

Thus, PQ cannot give us an expression equivalent to 23y⁴ - 6y³ + 35y² - 20y.

P - Q:

P = 8y⁴ + 6y³ + 8y

Q = (5y² - 4y)(3y² + 7) = (15y⁴ + 35y² - 12y³ - 28y)

P - Q = (8y⁴ + 6y³ + 8y) - (15y⁴ + 35y² - 12y³ - 28y)

Open parentheses

8y⁴ + 6y³ + 8y - 15y⁴ - 35y² + 12y³ + 28y

Collect like terms

8y⁴ - 15y⁴ + 6y³ + 12y³ - 35y² + 8y + 28y

-7y⁴ + 18y³ - 35y² + 36y

Therefore, P - Q cannot give us an expression equivalent to 23y⁴ - 6y³ + 35y² - 20y.

P + Q:

P = 8y⁴ + 6y³ + 8y

Q = (5y² - 4y)(3y² + 7) = (15y⁴ + 35y² - 12y³ - 28y)

P + Q = (8y⁴ + 6y³ + 8y) + (15y⁴ + 35y² - 12y³ - 28y)

Open parentheses

8y⁴ + 6y³ + 8y + 15y⁴ + 35y² - 12y³ - 28y

Collect like terms

8y⁴ + 15y⁴ + 6y³ - 12y³ + 35y² + 8y - 28y

23y³ - 6y³ + 35y² - 20y

Therefore, P + Q will result in an expression equivalent to 23y⁴ - 6y³ + 35y² - 20y.

The answer is D.

7 0
2 years ago
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