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2 years ago

Help me pls i don’t know the answer

Mathematics

2 answers:

sleet_krkn [62]2 years ago

8 0

Answer:

Step-by-step explanation:

$10 \log( \frac{106.8}{1 \times {10}^{ - 12} } ) \approx 140$

Anit [1.1K]2 years ago

7 0

Letter D. Is the correct answer

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Find the amount in an account if $45,050 is invested at 7.001% compounded quarterly, for 12 years and 3 months.

Korolek [52]

$A=P(1+ \frac{r}{n})^{tr}$
a=future amount
p=present amount
r=rate in decimal
n=number off time per year compouonded
t=time in years

P=45,050
r=0.07001
n=4
t=1.25

$A=45,050(1+ \frac{0.07001}{4})^{(1.25)(4)}$
$A=45,050(1+ 0.0175025)^{5}$
$A=45,050(1.0175025)^{5}$
A=49132.8798
round
A=$49,132.88

4 0

3 years ago

There are 4 different methods you could use to solve a quadratic equation that would depending upon the actual equation. They ar

lana66690 [7]

Answer:

Part A: x^2 + 6x + 8 = 0 use the factoring the equation method

Part A: x^2 + 6x + 8 = 0 use the quadratic formula

Step-by-step explanation:

Part A;

The equation is x^2 + 6x + 8 = 0 , looking at this quadratic expression, you notice it is written in a quadratic equation standard form of ax^2+bx+c=0. Additionally, you notice that can find what multiplied to get the quadratic equation,factor.You can identify two numbers that multiply to get ac and add to give b.In this question;

a=1,b=6,c=8

ac=8

The numbers are 4 and 2. Factoring the equation method will give;

x²+6x+8=0

x²+4x+2x+8=0

x(x+4)+2(x+4)=0

(x+2)+(x+4)=x²+6x+8

x+2=0, x=-2 and x+4=0, x=-4

Part B

The quadratic equation is ;

x²+6x-11=0

You notice that there are no factors that multiply direct to get the quadratic equation like in part 1. When you observe, a=1, b=6 and c=-11

ac=1×-11=-11 and b=6 .You notice there are no factors that multiply to give -11 and add to get 6, hence the factorizing the equation method can not be used.However, you can apply the quadratic formula that requires coefficients. You have a=1, b=c and c=-11 as the coefficients to use in the quadratic formula.

8 0

3 years ago

Read 2 more answers

A street light is mounted at the top of a 15-ft-tall pole. A man 6 feet tall walks away from the pole with a speed of 5 ft/s alo

harina [27]

Answer:

25/3 ft/s

Step-by-step explanation:

Height of pole , h=15 ft

Height of man, h'=6 ft

Let BD=x

BE=y