The numeric values of the function are given as follows:
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How to find the numeric value of a function?</h3>
To find the numeric value of a function, we replace each instance of the variable by the desired value.
In this problem, the function is given by:
![q(t) = \frac{4t^2 + 5}{t^2}](https://tex.z-dn.net/?f=q%28t%29%20%3D%20%5Cfrac%7B4t%5E2%20%2B%205%7D%7Bt%5E2%7D)
When t = 2, the numeric value is:
q(2) = [4(2)² + 5]/2² = 5.25.
When t = 0, the numeric value is:
q(0) = [4(0)² + 5]/0² = Undefined, as division by 0 does not exist.
When t = -x, the numeric value is:
q(-x) = [4(-x)² + 5]/(-x)² = (4x² + 5)/x².
More can be learned about the numeric value of a function at brainly.com/question/28276964
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