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Norma-Jean [14]
2 years ago
9

In a football tournament, each team played exactly 19 games. Teams get three points for everyone and one point for every time. A

t the end of the tournament, team Olympus got a total of 28 points. How many could team Olympus have tied?
Mathematics
1 answer:
irinina [24]2 years ago
7 0

We can actually deduce here that when the tournament ended, team Olympus have tied for 13, 10, 7, 4, 1 times.

<h3>What is inequality?</h3>

In Mathematics, inequality is used to express or show quantities that are less than, greater than, greater than or equal to,  less than or equal to.

The following can be seen in inequality expressions:

  • ≤
  • ≥
  • >
  • <
  • ≠

Looking at the question, we can see that each team plays exactly 19 games.

Every win (w) = 3

Every tie (t)= 1

Every loose = 0

But Olympus got a total of 28 points

Thus: 3w + t = 28 ---------(1)

Note that each team plays  19 games

Thus, T + W  ≤  19 --------------(2)

and T , W ≥ 0

Looking at equation (1) and (2)

=> 2W  ≥  9

=> W ≥ 4.5  

( match can be won in integers only )

=> W  ≥  5  

W - 5, 6, 7, 8, 9    

T - 13, 10, 7, 4, 1  

Loose - 1, 3, 5, 7, 9

Thus, team Olympus have tied for 13, 10, 7, 4, 1 times.

Learn more about inequality on brainly.com/question/27771009

#SPJ1

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