Answer:
A) Average weight = 112.97
standard deviation = 3.913
B) 119.4069
Step-by-step explanation:
A) Estimate the true average weight and standard deviation of the weight
attached below is a detailed solution
Average weight = 112.97
standard deviation = 3.913
B) Assuming a normal distribution Estimate the weight below
attached below is a detailed solution
= 119.4069
For points (x1,y1) and (x2,y2)
slope=(y1-y2)/(x1-x2)
(-4,-13)
(19,11)
x1=-4
y1=-13
x2=19
y2=11
slope=(-13-11)/(-4-19)=-24/-23=24/23
B is answer
Answer:
I think the answer would be $3
Step-by-step explanation:
<span>The first step in determining the answer will need to be to convert the weight from imperial to metric.
12lbs ~ 5.44311kg
Then we need to look at the total amount of amoxicillin needed. At 5mg/kg is ~27.5mg twice per day.
The concentration is 50mg per ml. Knowing that the cat needs around 55mg, that leads us to 1.1ml daily.</span>
Answer:
2*square root of 2
Step-by-step explanation:
The square root of 8 is equal to 2*square root of 2