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2 years ago

If anybody could help me please :,) will give brainliest + 100 points

Mathematics

1 answer:

Alinara [238K]2 years ago

8 0

Answer:

P(B and D) = 0.35

Step-by-step explanation:

It is a probability tree diagram. Here to find P(B and D):

apply method:

P(A and B) = P(A) × P(B)

Here given:

P(B) = .5

P(D) = .7

So, P(B and D):

P(B) × P(D)

.5 × .7

.35 ≈ 0.35

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How do I subtract 4m^2 + 2mn + 8n^2 from 2m^2 + 6mn + 2n^2 ?

SVETLANKA909090 [29]

$-2m^2+4mn-6n^2$

1) Let's write out both expressions subtracting 4m²+2mn+8n² from 2m²+6mn+2n²

$\begin{gathered} 2m^{2}+6mn+2n^{2}-(4m^{2}+2mn+8n^2)_{} \\ 2m^2+6mn+2n^2-4m^2-2mn-8n^2 \\ -2m^2+4mn-6n^2 \end{gathered}$

2) Note that when we subtract 4m^2 + 2mn + 8n^2 from 2m^2 + 6mn + 2n^2 we need to swap the sign by placing -1 outside the parentheses and then combine like terms adding those terms algebraically.

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2 years ago

What is the answer to this question it doesn't state the answer so can you please tell me the answer

DiKsa [7]

I DONT KNOW JUST STRAT WITH THE BEGGINIG OF THE SENTENCE

5 0

3 years ago

Read 2 more answers

the length of a rectangle is 7 inches greater than three times its width write an expression to represent its area

icang [17]

Step-by-step explanation:

Let the length be L.

Let the breath be B.

So, we are given that

length of a rectangle is 7 inches greater than three times its width .

So, according to the Question,

L = 7+ 3B.

So, we know that:-

Area = Length× Breadth.

So, it will be

B × (7 + 3B) = Area.

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4 years ago

Jane wishes to bake an apple pie for dessert. The baking instructions say that she should bake the pie in an oven at a constant

Viktor [21]

Answer:

Therefore $k= \frac{ln2 }{18}$ , A=184

Step-by-step explanation:

Given function is

$T(t)=230 -e^{-kt}$

where T(t) is the temperature in °C and t is time in minute and A and k are constants.

She noticed that after 18 minutes the temperature of the pie is 138°C

Putting T(t) =138°C and t= 18 minutes

$138=230 -Ae^{-k\times 18}$

$\Rightarrow -Ae^{-18k}=138-230$

$\Rightarrow Ae^{-18k}=92$ .....(1)

Again after 36 minutes it is 184°C

Putting T(t) =184°C and t= 36 minutes

$184=230-Ae^{-k\times 36}$

$\Rightarrow Ae^{-36k}=230-184$

$\Rightarrow Ae^{-36k}=46$ .......(2)

Dividing (2) by (1)

$\frac{Ae^{-36k}}{Ae^{-18k}}=\frac{46}{92}$

$\Rightarrow e^{-18k}=\frac{46}{92}$

Taking ln both sides

$ln e^{-18k}=ln\frac{46}{92}$

$\Rightarrow -18k =ln (\frac12)$

$\Rightarrow -18k= ln1-ln2$

$\Rightarrow k= \frac{ln2 }{18}$

Putting the value k in equation (1)

$Ae^{-18\frac{ln2}{18}}=92$

$\Rightarrow A e^{ln2^{-1}}=92$

$\Rightarrow A.2^{-1}=92$

$\Rightarrow \frac{A}{2}=92$

$\Rightarrow A= 92 \times 2$

⇒A= 184.

Therefore $k= \frac{ln2 }{18}$ , A=184

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3 years ago

What is 689 divided by 53

Vladimir [108]

689:53=13
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3 years ago

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