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love history [14]
1 year ago
11

Select the correct answer. to solve this system of equations using substitution, what could be substituted in place of y in the

first equation? 4x = 5 − 2y y − 2x = 7
Mathematics
1 answer:
Rina8888 [55]1 year ago
3 0

To use substitution to evaluate this system of equations, the y value to be substituted is 2x - 7.

<h3>What is method of substitution?</h3>

The algebraic method for solving simultaneous linear equations is the substitution method. The values of one variables from one expression is substituted with in second equation, as the name implies.

Now according to the question;

The expressions are as follows;

4x = 5 – 2y and y – 2x + 7 = 0

To solve the following system of equations, we must determine what substitution must be made in place of y in the first equation.

Let us now deduce the value of y from the second equation.

y – 2x + 7 = 0 ⇒ y = 2x – 7

We now have the y value, which we can plug into the first equation;

⇒ 4x = 5 – 2(2x – 7)

4x = 5 – 4x + 14

4x + 4x = 5 + 14

8x = 19

x = 19/8

Substitute the value of x in y to get its value.

y = 2×(19/8) - 7

y = -9/4

Thus, the values obtained for the given set of equations are-

x = 19/8 and y = -9/4 by method of substitution.

To know more about method of substitution, here

brainly.com/question/22340165

#SPJ4

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A cone has a base with a radius of 9 mm and a height of 13 mm. What is the volume of the cone?
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\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}

  • Given - <u>a </u><u>cone </u><u>with </u><u>base </u><u>radius </u><u>9</u><u>m</u><u>m</u><u> </u><u>and </u><u>height </u><u>1</u><u>3</u><u> </u><u>mm</u>

  • To calculate - <u>volume </u><u>of </u><u>the </u><u>cone</u>

We know that ,

Volume \: of \: cone =  \frac{1}{3}\pi \: r {}^{2}  h \\

<u>su</u><u>b</u><u>stituting </u><u>the </u><u>values</u><u> </u><u>in </u><u>the </u><u>formula</u><u> </u><u>,</u>

Volume =  \frac{1}{3}  \times  3.14  \times 9 \times 9 \times 13 \\  \\  \implies \: 1.05 \times 81 \times 13 \\  \\ \implies \: 1105.65 \: mm {}^{3}

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