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Sergeu [11.5K]
2 years ago
5

avery is constructing an inscribed square in a circle. part a: where did avery place the pivot point of his compass to create th

e two sets of arcs? explain your answer. (3 points) part b: how wide did avery stretch the compass to create the two sets of arcs? explain your answer. (3 points) source stylesformatfontsize
Mathematics
1 answer:
rjkz [21]2 years ago
5 0

The radius of the circle will be half of the diagonal length.

first of all Avery has to attract a square after which draw the diagonals of the square.

Now, mark the point at which the diagonal cuts each other. setting one stop of the compass at that point and other cease at the vertex of the square draw the specified circle to be able to have the radius equal to the half of of the diagonal.

Let the side of the square is a units. Then the length of the diagonal =1.414× Side of square

= 1.414×a

So, the radius of the circle will be =[(1.414×a)/2]

                                                        = 0.707a units

Hence, the required radius is 0.707a units.

To learn more about circles and squares visit the link:

brainly.com/question/16592747

#SPJ4

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3( x -5)- 5x= 25+ 6x What is the answer and how do you solve this??
stiks02 [169]
1.) expand

3x - 15 - 5x = 25 + 6x

2.) simplify

-2x - 15 = 25 + 6x

3.) add 2x to both sides

-15 = 25 + 6x + 2x

4.) simplify

-15 = 25 + 8x

5.) subtract 25 from both sides

-15 - 25 = 8x

6.) simplify -15 - 25 to -40

-40 = 8x

7.) divide both sides by 8

-40/8 = x

8.) x = -5


7 0
3 years ago
Solve the x <br> 1/3x + 5&gt; 10
kotykmax [81]

Answer:

The solution to the inequality is:

\frac{1}{3}x+5>10\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x>15\:\\ \:\mathrm{Interval\:Notation:}&\:\left(15,\:\infty \:\right)\end{bmatrix}

The solution graph is also attached below.

Step-by-step explanation:

Given

We are given the expression

\frac{1}{3}x+5>10

To determine

Solve for x

Given the expression

\frac{1}{3}x+5>10

Subtract 5 from both sides

\frac{1}{3}x+5-5>10-5

Simplify

\frac{1}{3}x>5

Multiply both sides by 3

3\cdot \frac{1}{3}x>5\cdot \:3

Simplify

x>15

Thus, we conclude that:

x>15

Therefore, the solution to the inequality is:

\frac{1}{3}x+5>10\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x>15\:\\ \:\mathrm{Interval\:Notation:}&\:\left(15,\:\infty \:\right)\end{bmatrix}

The solution graph is also attached below.

5 0
3 years ago
Factor completely p^2-13p+42
ira [324]
Factoring the expression would look like this : 
(p - 7) (p - 6)
5 0
3 years ago
The admission fee at an amusement park is $1.75 for children and $4.80 for adults. On a certain day, 303 people entered the park
Nookie1986 [14]

Answer:

Children 188

Adults. 115

Step-by-step explanation:

Let the no. of children be x and adults be y

x + y = 303

x = 303 - y. .... .....(1)

1.75x + 4.80y = 881. ...........(2)

Substituting,

1.75(303-y) +4.80y = 881

530.25 -1.75y + 4.80y = 881

530.25 + 3.05y = 881

3.05y = 881 - 530.25

y = 350.75 / 3.05 = 115 = adults

Children = 303-115 = 188

3 0
3 years ago
Ana's statistics skills have been improving during her senior year at Fletcher High School. On her first end-of-the-week assessm
Virty [35]
It will be 89 because it increases by 4 each time
5 0
3 years ago
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