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Nataly_w [17]
1 year ago
6

Read paragraphs 4-5 from the passage.

Mathematics
1 answer:
rodikova [14]1 year ago
3 0

Answer:  C

Step-by-step explanation:

I recognize this as coming from an old 1912 novel published as "A Princess of Mars", by Edgar Rice Burroughs. I read the book as a teenage boy. A 2012 movie, called "John Carter", was based on this same book.

Answer A  - No, because the character (Carter) says, "My muscles, perfectly attuned and accustomed to the force of gravity on Earth". Perfectly attuned is an athlete, not a clumsy person.

Answer B - No, because the character just doesn't sound all that frustrated. The experience is strange and inconvenient, yet he is handling his emotions pretty well for how weird it must be. It is more like he is writing about an amazing experience, not just complaining.

Answer D - No, because he never says that the experience was making him happy. He does not say that he was laughing or smiling or that it reminded him of some pleasant time he had as a boy.

Answer C - Yes. - Creation of vivid imagery. In a novel, the author must paint pictures with their words. Part of how the author does this is by giving you the picture of a man who feels very comfortable with his coordination on Earth, but keeps winding up about 9 feet off the ground without trying. He doesn't just "I kept falling". He tells you in vivid detail - "... landed me sprawling on my face or back ..."

Hope this helps!

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A road has a 10% grade, meaning increasing 1 unit of rise to every 10 units of run.
fenix001 [56]

The grade is the ratio of rise to run, i.e. the slope aka the tangent.

\tan \theta = \dfrac{1}{10}

\theta = \arctan 0.1 \approx 5.711^\circ

Answer: (a) 6 degrees

For part b, the road is the hypotenuse c of a right triangle whose tangent of the small angle is 1/10.    The height h or rise is the side opposite the small angle.

\sin\theta = \dfrac h c

h = c \sin \theta

We could just take the sine of the angle we got but let's get it from the tangent exactly.

\cos^2 \theta + \sin ^2 \theta = 1

Dividing by squared cosine

1 + \tan ^2 \theta = 1/\cos^2 \theta = 1/(1- \sin^2 \theta)

(1- \sin^2 \theta) = 1/(1 + \tan^2 \theta)

\sin^2 \theta = 1 - 1/(1 + \tan^2 \theta)

\sin^2 \theta = 1 - 1/(1 + (1/10)^2) = 1-1/(101/100) = 1/101

h = c \sin \theta = 2 \sqrt{1/101} \approx 0.199

Answer: (b) Rise of 0.199 km

6 0
3 years ago
Lnes made9 necklaces with 60 beads on each necklaces. How many beads did she use in all
Gala2k [10]
Made 9  necklaces.
60 beads per necklace.
How many beads for all the 9 necklaces?

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9 necklaces = 540 beads<span />
3 0
2 years ago
How do i know that the variable x has a uniform distribution function?
Evgen [1.6K]
You will have to solve for x to know what x equals 
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3 years ago
In​ 2012, the population of a city was 6.27 million. The exponential growth rate was 1.47​% per year.
Tcecarenko [31]

Answer:

a) a(t)= 6.27e^{0.0147*t}

b) 6.84 million

c) 2028.52

d) 47 years

Step-by-step explanation:

a)Here we know standard exponential growth rate is

a(t)= ae^{k*t}

In this put t=0 and a(t)=6.27 million

thus we get a = 6.27 million

now \frac{da}{dt}=a(t)k

  this is equal to(in 2012)=\frac{1.47}{100}*=0.0147

b)Put t = 6

we get

a(t)= 6.27e^{0.0147*6}

=6.84 million

c) 8 = 6.27e^{0.0147*t}

  take log both sides

we get 16.52 years

d) 2*6.27=6.27e^{0.0147*t}

take log both sides we get 47 years to get double the current population.

3 0
2 years ago
What is 12-2x6 + 2/2 ?
garri49 [273]
12-2*6 + \frac{2}{2}= \\&#10;12-12+1 = 0 + 1 = 1
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