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1 year ago

Find the midpoint of the segment with the given endpoints. (6,-6) and (1,2)

Mathematics

1 answer:

MrRissso [65]1 year ago

5 0

The midpoint of the line segment of the endpoints (6,-6) and (1,2) is given as:

(3½,-1)

What is the midpoint of a line segment in geometry?

The midpoint of a line segment is simply the centre point of a give segment that cuts or divides it into two congruent segments.

That is for example, if there are two points with coordinates (x1,y1) and (x2,y2), then their midpoint will be ; [(x1+x2)÷2,(y1+y2)÷2]

From the given question!

x1=6, x2=1 and y1=-6,y2=2

Thus, the midpoint is derived as;

[(6+1)÷2,(-6+2)÷2]

[(7)÷2,(-4)÷2]

(3½,-1).

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3 years ago

Write an recursive formula for An, the nth term of the sequence<br> 5, -2, -9,

oksian1 [2.3K]

Given:

The given sequence is:

$5,-2,-9,...$

To find:

The recursive formula for $a_n$ , the nth term of the sequence.

Solution:

We have,

$5,-2,-9,...$

Here, the first term is 5.

$-2-5=-7$

$-9-(-2)=-9+2$

$-9-(-2)=-7$

The common difference is -7.

The recursive formula for the nth term of the sequence is

$a_n=a_{n-1}+d$

Where, $d$ is the common difference.

Putting $d=-7$ in the above formula, we get

$a_n=a_{n-1}+(-7)$

$a_n=a_{n-1}-7$

Therefore, the recursive formula for the nth term of the sequence is $a_n=a_{n-1}-7$ .

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2 years ago

Please help,

Vesnalui [34]

Try 1(18) / 2

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Step-by-step explanation:

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