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barxatty [35]
3 years ago
10

What is the value of x2+3x-7 when x = -4?

Mathematics
1 answer:
ivann1987 [24]3 years ago
8 0

Answer:

\huge{ \fbox{ \sf{ - 3}}}

Step-by-step explanation:

\underline{ \text{Given}} :

\longrightarrow{ \sf{ \: x =  - 4}}

\underline{ \text{To \: find}} :  \: \sf{Value \: of \: the \: given \: expression}

\sf{ {x}^{2}  + 3x - 7}

\text{Step \: 1} : Plug the value of x

\sf{ {  \mapsto (  - 4)}^{2}   + 3 * \: ( - 4) \:  - 7}

\text{Step \: 2} : Evaluate the power

\underline{ \text{Remember!}} : Multiplying a negative integer by a negative integers gives a positive integer.

\mapsto{ \sf{16 + 3 \: * \: ( - 4) - 7}}

\text{Step \: 3} : Multiply : 3 by -4

\underline{ \sf{Remember!}} : Multiplying positive integer by any negative integer gives a negative integer.

\mapsto{ \sf{16 + ( - 12) - 7}}

\underline{ \text{Remember!}} : ( + ) * ( - ) = ( - )

\mapsto{ \sf{16 - 12 - 7}}

\text{Step \: 4} : Subtract 12 from 16

\mapsto{ \sf{4 - 7}}

\text{Step \: 5} : Subtract 7 from 4

\underline{ \text{Remember!}} : The negative and positive integers are always subtracted but posses the sign of the bigger integer.

\mapsto{ \boxed{ \sf{ - 3}}}

Remember to follow PEMDAS

Parentheses , Exponents , Multiplication , Division , Addition , Subtraction

Hope I helped!

Best regards! :D

~\text{TheAnimeGirl}

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Step-by-step explanation:

\overline{DA} \text{ bisects } \overline{EB}     is given

\overline{BC} \cong \overline{EC}  definition of <u>bisect</u>

<u />\overline{EB} \perp \overline{ED}, \, \overline{EB} \perp \overline{BA}  are both given

<u />\angle B, \, \angle E \text{ are right angles}  definition of perpendicular

\angle B \cong \angle E   because all right angles are congruent

\angle{ACB} \cong \angle{DCE}  vertical angles are congruent

\triangle{ACB} \cong \triangle{DCE}   ASA (angle-side-angle)

\overline{ED} \cong \overline{BA}  CPCTC (corresponding parts of congruent triangles are congruent)

5 0
3 years ago
9/11 - 1/2 in it's simplest form​
Murrr4er [49]

Answer:

7/22

Step-by-step explanation:

Step 1: <u>Define/explain.</u>

To subtract fractions with different denominators, you must first find the least common denominator (LCM).

You can do this by listing the multiples of each denominator.

Step 2: <u>Solve.</u>

11: 11, 22, 33, 44, 55, 66, 77, 88, 99, 110

2: 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22

22 is the LCM.

Now, we change the fractions to where they both have denominators of 22.

**REMEMBER: WHICHEVER NUMBER YOU MULTIPLY THE DENOMINATOR BY, YOU MULTIPLY IT BY THE NUMERATOR AS WELL!!**

9/11*2/2=18/22

1/2*11/11=11/22

Now, subtract as normal.

18/22-11/22=7/22

7/22 (simplified).

Step 3: <u>Conclude.</u>

Therefore, 9/11 - 1/2 = 7/22.

5 0
3 years ago
If the numerator of a fraction is increased by 3, the fraction becomes 3/4. If the denominator is decreased by 7, the
Sauron [17]

7 over 1

Step-by-step explanation:

3 0
4 years ago
Which transformations could have occurred to map AABC
babymother [125]

Answer:

A reflection and a dialation

Step-by-step explanation:

  1. Reflection is when you flip a figure over a line.
  2. Rotation is when you rotate a figure a certain degree around a point.
  3. Dilation is when you enlarge or reduce a figure.

In this case a rotation is not nessasary, so I would suggest a reflection in the y-axis and a dialation to shrink the triangle to A'B'C'

So for the transformations that could have occurred to map ABC to A'B'C' you should choose the answer

a reflection and a dialation

5 0
3 years ago
Read 2 more answers
Circle O and circle P are congruent. Given that arc AB is congruent to arc DE, what can you conclude from the diagram?
wlad13 [49]

Answer:

Central angle is equal in both circles

And the two triangles inscribed in circle is congruent.

Step-by-step explanation:

We have been given the two circles which are congruent O and P.

Ab is congruent to DE

So, the central angle of two circles will be equal circles being congruent.

And the two triangles AOB and EPD are congruent

Radius of the congruent circle is equal

Hence, OB=PD

             AB=DE

And ∠BOA=∠DPE

By SAS property ΔAOB ≅ΔEPD


5 0
4 years ago
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