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Lapatulllka [165]
2 years ago
8

1 ejemplo en donde se aplique las medidas de tendencia central (moda, media y mediana)

Mathematics
1 answer:
Mamont248 [21]2 years ago
5 0

An example of a situation where the measures of central tendency can be applied is when analyzing the test scores of a Math exam taken by 11 people.

<h3>What is an example of measures of central tendency in use?</h3><h3 />

Assuming that 11 people took a Math exam that was graded out of 20 and got the results:

6, 8, 9, 10, 10, 14, 15, 15, 15, 18, 18

The median in this set would be 14. This would therefore show us what the person with the middle score got which is useful in knowing the whether people were above the middle score, or below it.

The mode in this dataset is 15 which shows that 15/20 was the score that was most acquired by people who took the exam.

The mean is:

= (6 + 8 + 9 + 10 + 10 + 14 + 15 + 15 + 15 + 18 + 18) / 11

= 12.5

On average therefore, people got a score of 12.5 in this example. This gives an overall view of the difficulty of the exam.

Find out more on the measures of central tendency at brainly.com/question/17631693

#SPJ1

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Express 110111 base two to base ten​
lidiya [134]

Answer:

zh

Step-by-step explanation:

4 0
3 years ago
Can someone help me
defon
Answer for problem 46 is choice A
Answer for problem 47 is choice B
Answer for problem 48 is choice E

-----------------------------------------------------------------------------
-----------------------------------------------------------------------------

Work Shown

Problem 46
Equation 1: 3x+y = 17
Equation 2: x+3y = -1
Add equation 1 to equation 2 to get 4x+4y = 16. Divide every term by 4 to get x+y = 4. Then finally multiply both sides by 3 to get 3x+3y = 12
That shows why the answer is choice A

---------------------------------
Problem 47)

If y hours pass by, then y-(2/3)y=y/3 is the time value (2/3)y hours ago

So,
Distance = rate*time
d = r*t
d = x*(y/3)
d = (xy)/3
That's why the answer is choice B

---------------------------------
Problem 48)
Let L1,L2,L3 be the three lists where
L1 = {a1,a2,a3,...,ak} there are k scores here
L2 = {a1,a2,...,a10} there are 10 scores here
L3 = {a11,a12,...,ak} the remaining k-10 scores
S(L1) = sum of the scores in list L1
M(L1) = mean of L1 = 20 = S(L1)/k
M(L2) = mean of L2 = 15 = S(L2)/10
S(L1) = 20k
S(L2) = 150
S(L1) = S(L2)+S(L3)
M(L1) = [S(L2)+S(L3)]/k
20 = [150+S(L3)]/k
20k = 150+S(L3)
S(L3) = 20k-150
M(L3) = [S(L3)]/(k-10)
M(L3) = (20k-150)/(k-10)
So that shows why the answer is choice E
3 0
4 years ago
Find the solution to 20 - (-3) - 10 - 6+3 - (-2) - 3.<br> O 10<br> 0 -9<br> O -5<br> O 9
iragen [17]

Answer:

O 9

Step-by-step explanation:

Subtracting a negative turns it into addition. So this becomes 20 + 3 - 10 - 6 + 3 + 2 - 3.

Going through this problem looks like this: 23 - 10, 13 - 6, 7 + 3, 10 + 2, 12 - 3. And you get 9.

4 0
3 years ago
Read 2 more answers
What is the distance between the points (-1,-7) and (-1,4)
vredina [299]

Hello from MrBillDoesMath!

Answer:

11

Discussion:

Solution by distance formula:

d = sqrt( (x2-x1)^2 + (y2-y1)^2)

  = sqrt (  (-1 - (-1) )^2 + (4 - (-7))^2 )

  = sqrt (   ( -1 + 1) ^2 + (4+7)^2)

  = sqrt (   0^2           + 11^ 2    )

  = sqrt ( 11^2)

  = 11

Solution by contemplation!

Note the x coordinate of both points is the same (i.e. -1)  This means the line joining the points is vertical and its length is simply the difference of the y coordinates:   4 - (-7) = 4 + 7 = 11

Thank you,

MrB

4 0
3 years ago
Read 2 more answers
Which of the following phrases are expression
11Alexandr11 [23.1K]

Answer:

B, D, E

Step-by-step explanation:

B, D, and E are sentences with a minimum of two numbers and at least one math operation, an expression.

6 0
3 years ago
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