In case of Nina:
slope of graph = speed = 48-32/6-4 = 16/2 =8
y-32 =8(x-4)
y-32=8x-32
y=8x
d=8t
at x= 0 i.e at t= 0
d= 0m
In case of Ryan:
slope =speed = 47.5-35=6-4 = 12.5/2 =6.25
y-35=6.25(x-4)
y-35=6.25x-25
y=6.25x+10
d=6.25t+10
at t = 0, d= 10m
RYAN had a head start of 10 m
Answer:
r=17%
Step-by-step explanation:
P is the investment
A is the targeted amount
t= time (25-18=7 years)
A=P(1+r)^t
30000=10000(1+r)^7
(1+r)^7=30000/10000
r=\root(7)(3)-1
r=0.16993 ≅0.17= 17%
check: A=P(1+r)^t ⇒10000(1+0.17)^7=30012≅30000
Answer:
School A
Step-by-step explanation:
School A has a ratio of 18/225 = 2/25 staff to students
School B has a ratio of 23/322 = 2/28 = 1/14 staff to students
Assuming that a better ratio means more staff per students School A has a better ratio
F,e and h,i are vertical angles i think.
Answer:
a) 1 cupcake = $5.50
b) 1 Popsicle = $3.50
Step-by-step explanation:
Let s = cost of one soda
Let c = cost of one cupcake
Let p = cost of one Popsicle
From the given information we can create 3 equations:
- Equation 1: s + c + p = 22
- Equation 2: s + 3c + 3p = 40
- Equation 3: c = p + 2
Subtract Equation 1 from Equation 2 to eliminate the variable s:
s + 3c + 3p = 40
<u>- s + c + p = 22</u>
<u> 2c + 2p = 18</u>
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Substitute Equation 3 into this new equation and solve for p:
⇒ 2c + 2p = 18
⇒ 2(p + 2) + 2p = 18
⇒ 2p + 4 + 2p = 18
⇒ 4p = 14
⇒ p = 3.5
Substitute the found value of p into Equation 3 and solve for c:
⇒ c = p + 2
⇒ c = 3.5 + 2
⇒ c = 5.5
To find the cost of a soda (s), substitute the found values of p and c into Equation 1:
⇒ s + c + p = 22
⇒ s + 5.5 + 3.5 = 22
⇒ s = 13
Therefore,
- 1 soda costs $13
- 1 cupcake costs $5.50
- 1 Popsicle costs $3.50
