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andrew11 [14]
1 year ago
5

Surface area of rectangular prism length=6m breath=4 height= 2​

Mathematics
2 answers:
Vanyuwa [196]1 year ago
7 0

Step-by-step explanation:

as with dice (as a special quadratic form of a prism) such a prism has 6 sides :

top and bottom

left and right

front and back.

all we need to do is calculate the areas of the 6 sides and add them up for the total surface area. that's all that's needed.

it is not specified, but I assume this prism to be regular, as there is no additional information provided. that means the rectangles in each of the mentioned pairs are equal.

therefore we need to calculate the area only once and multiply it by 2.

so,

top and bottom :

2 × 6×4 = 2 × 24 = 48 m²

left and right :

2 × 4×2 = 2 × 8 = 16 m²

front and back :

2 × 6×2 = 2 × 12 = 24 m²

the total surface area of the prism is

48 + 16 + 24 = 88 m²

katen-ka-za [31]1 year ago
4 0

Answer:

TSA = 88

Step-by-step explanation:

Formula we use,

→ TSA = 2(lb + bh + lh)

The TSA of rectangular prism will be,

→ 2(lb + bh + lh)

→ 2[(6 × 4) + (4 × 2) + (6 × 2)]

→ 2(24 + 8 + 12)

→ 2 × 44 = 88

Hence, the TSA is 88.

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Need help for number 4 please
Marina CMI [18]

Answer:

Step-by-step explanation:

4) ΔSTW ≅ ΔBFN . So, corresponding parts of congruent triangles are congruent.

a) BN = SW                                        d) m∠W = m∠N

  BN = 9 cm                                           m∠W = 82°

b) TW = FN                                        e) m∠B = m∠S

TW = 14 cm                                            m∠B = 67°

c) BF = ST                                          f) m∠B + m∠N + m∠F = 180°

  BF = 17 cm                                                 67 + 82 + m∠F = 180

                                                                            149 + m∠F = 180

                                                                                     m∠F = 180 - 149

                                                                                      m∠F = 31°          

5) ΔUVW ≅ ΔTSR

UV = TS

12x - 7 = 53

   12x   = 53+7

   12x = 60

      x = 60/12

      x = 5

UW =TR

3z +14 = 50

    3z = 50 - 14

   3z = 36

     z = 36/3

    z = 12

SR =VW

5y - 33 = 57

     5y = 57 + 33

     5y = 90

       y = 90/5

       y = 18

7) ΔPHS ≅ ΔCNF

∠C = ∠P

4z - 32 = 36

      4z = 36 + 32

       4z = 68

        z = 68/4

       z = 17

∠H = ∠N

6x - 29 = 115

  6x     = 115 + 29

      6x = 144

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∠P + ∠H + ∠S = 180   {Angle sum property of triangle}

36 +115 + ∠S = 180

      151   + ∠S = 180

                ∠S = 180 - 151

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∠F = ∠S

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8) ΔDEF ≅ ΔJKL

DE = 18    ;  EF = 23

DF = 9x - 23

JL= 7x- 11

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9x  - 7x - 23 = -11

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                x = 6      

JK   = DE           {Corresponding parts of congruent triangles}

3y - 21  = 18

       3y = 18 + 21

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