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OverLord2011 [107]
1 year ago
15

William and Debra Pierce are celebrating their 20th anniversary by having a reception at a local reception hall. They have budge

ted $2,500 for their reception. If the reception hall charges a $100 cleanup fee plus $38 per person, find the greatest number of people that they may invite and still stay within their budget.
William and Debra can invite at most ____ people to the reception.

Please help asap! This is due today and I need help to better understand this. Tysm!
Mathematics
1 answer:
erica [24]1 year ago
5 0

The greatest number of people that William and Debra may invite and still stay within their budget is 63.

<h3>What is an equation?</h3>

An equation is formed when two equal expressions are equated together with the help of an equal sign '='.

Since William and Debra have budgeted $2,500 for their reception. Therefore, their total expenses should be equal to the total expenses in the reception.

Budget = Total expenses

Budget = Reception hall Cleanup charge + $38 per person fee

Let the number of people invited to the party be represented by x,

$2,500 = $100 + $38(x)

2500 = 100 + 38x

2500 - 100 = 38x

2400 = 38x

x = 2400 / 38

x = 63.157 ≈ 63

Hence, the greatest number of people that William and Debra may invite and still stay within their budget is 63.

Learn more about Equation here:

brainly.com/question/14686792

#SPJ1

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3 X 10 = 30/2 = 15

area: 15yd^2

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3 years ago
Read 2 more answers
PLEASE HELP 30 POINTS!!!!!!!!!!!!!!!!!!!!!!!
Anettt [7]

Since you know the value of "x", you can plug in the value for "x" in the equation.

[When an exponent is negative, you move it to the other side of the fraction to make the exponent positive.]

For example:

x^{-2}  or  \frac{x^{-2}}{1} =\frac{1}{x^2}

\frac{1}{y^{-3}} =\frac{y^3}{1}  or  y³


x = -2

f(x) = 9x + 7

f(-2) = 9(-2) + 7 = -18 + 7 = -11


g(x)=5^x

g(-2)=5^{-2}=\frac{1}{5^2}=\frac{1}{25}   (idk if you should have it as a decimal or a fraction)



x = -1

f(x) = 9x + 7

f(-1) = 9(-1) + 7 = -9 + 7 = -2


g(x)=5^x

g(-1)=5^{-1}=\frac{1}{5}



x = 0

f(x) = 9x + 7

f(0) = 9(0) + 7 = 7


g(x)=5^x

g(0)=5^0=1



x = 1

f(x) = 9x + 7

f(1) = 9(1) + 7 = 9 + 7 = 16


g(x)=5^x

g(1)=5^1=5



x = 2

f(x) = 9x + 7

f(2) = 9(2) + 7 = 18 + 7 = 25


g(x)=5^x

g(2)=5^2=25



You need to determine the solution of f(x) = g(x)

Since you know f(x) = 9x + 7 and g(x)=5^x, you can plug in (9x + 7) for f(x), and (5^x) into g(x)


f(x) = g(x)

9x+7=5^x   You can plug in each value of x into the equation


Your answer is x = 2 because when you plug in 2 for x in the equation, you get 25 = 25

5 0
3 years ago
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