All categories

10 months ago

Do number 13 please. Thank you

Mathematics

2 answers:

Ket [755]10 months ago

4 0

Answer:

I think the person above me is right not sure

Step-by-step explanation:

because I can't open the attachment I am sorry.

cluponka [151]10 months ago

3 0

Answer:

Step-by-step explanation:

a/2 subtracted from b = b-a/2 so D

You might be interested in

20 POINTSSSS

SVEN [57.7K]

Answer:

Really

Step-by-step explanation:

8 0

2 years ago

Find the midpoint of (0,4) and (-4,-12)

ankoles [38]

The answer is (-2,-4) to solve this you need to add the X’s and divide by 2 and that will be your X for the midpoint, you do the same with the Y’s to find the y for your midpoint

5 0

2 years ago

Determine the measure of each segment then indicate whether the statements are true or false

kupik [55]

Answer:

$d_{AB}\ne d_{JK}$

$d_{AB}\ne \:d_{GH}$

$d_{GH}\ne \:d_{JK}$

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

Step-by-step explanation:

Considering the graph

Given the vertices of the segment AB

A(-4, 4)

B(2, 5)

Finding the length of AB using the formula

$d_{AB}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$=\sqrt{\left(2-\left(-4\right)\right)^2+\left(5-4\right)^2}$

$=\sqrt{\left(2+4\right)^2+\left(5-4\right)^2}$

$=\sqrt{6^2+1}$

$=\sqrt{36+1}$

$=\sqrt{37}$

$d_{AB}\:=\sqrt{37}$

$d_{AB}=6.08$ units

Given the vertices of the segment JK

J(2, 2)

K(7, 2)

From the graph, it is clear that the length of JK = 5 units

$d_{JK}=5$ units

Given the vertices of the segment GH

G(-5, -2)

H(-2, -2)

Finding the length of GH using the formula

$d_{GH}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$=\sqrt{\left(-2-\left(-5\right)\right)^2+\left(-2-\left(-2\right)\right)^2}$

$=\sqrt{\left(5-2\right)^2+\left(2-2\right)^2}$

$=\sqrt{3^2+0}$

$=\sqrt{3^2}$

$\mathrm{Apply\:radical\:rule\:}\sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0$

$d_{GH}\:=\:3$ units

Thus, from the calculations, it is clear that:

$d_{AB}=6.08$

$d_{JK}=5$

$d_{GH}\:=\:3$

Thus,

$d_{AB}\ne d_{JK}$

$d_{AB}\ne \:d_{GH}$

$d_{GH}\ne \:d_{JK}$

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

8 0

2 years ago

16) Graph g(x) = x + 3 + 2

krek1111 [17]

X=1.6 just did the math

3 0

1 year ago

AREAS AND VOLUMES OF SIMILAR SOLIDS URGENT?

Llana [10]

Formula for the volume of cone is $\frac{1}{3} \pi r^2h$

Where r= radius of the cone

h = height of the cone

The value of pi is 3.14

Given volume of larger cone is 131 cm^3

Volume of larger cone = $\frac{1}{3} \pi r^2h$

131 = $\frac{1}{3} \pi 5^2h$

Solve for h

131 = 26.1667 *h

So h= 5 cm

The height of bigger cone = 5cm

Now we find the volume of smaller cone

Two cones similar so the sides are in proportional

$\frac{radius(small)}{radius(large)}= \frac{height(small)}{height(large)}$

$\frac{2}{5} =\frac{ height of small}{5}$

Height of smaller cone = 2cm

volume of smaller cone = $\frac{1}{3} \pi 2^2*2$

= 8.38cm^3

6 0

2 years ago