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VikaD [51]
1 year ago
4

Y=-cos(x+pi/4)amplitude period phase shift

Mathematics
1 answer:
Marina86 [1]1 year ago
6 0

Given the equation of the function:

y=-\cos (x+\frac{\pi}{4})

The graph of the function will be as shown in the following picture:

As shown in the figure:

The amplitude = 1

The period = 2π

The phase shift = π/4

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The function below is written in vertex form or intercept form. Rewrite them in standard form and show your work.
lora16 [44]

Answer:

The standard form as y=5x^2+30x+41

Step-by-step explanation:

Given: A function which is written in vertex form or intercept form.

We have to re-write it  in standard form that in terms of

Given y = 5(x+3)^2-4

Squaring  using (a+b)^2=a^2+b^2+2ab , we get,  

y=5(x^2+9+6x)-4

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y=5x^2+45+30x-4

Solving further , we get,

y=5x^2+30x+41

Thus , we have obtained the standard form as y=5x^2+30x+41







8 0
3 years ago
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Answer:

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Step-by-step explanation:

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From the diagram, the diameter is 8m.

This means that the radius is

r =  \frac{8}{2}  = 4m

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The area of shaded region is area of square minus area of circle.

Area \: of \: shaded \: region = 64 - 50.24 = 9.76 {m}^{2}

8 0
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Answer:

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Which expression is equivalent to 1/2r + 8p –3/4r – 2p?
Hunter-Best [27]

Answer:

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Step-by-step explanation:

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