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nlexa [21]
11 months ago
14

(Ch. 6, p. A man bought a trampoline for his children to use. The trampoline has a diameter of 17 feet. If the man wishes to put

up netting to go around the outside of the trampoline, how many feet of netting does he need? Give the exact circumference of the trampoline and then an approximation. Use 1.3.14. The exact circumference of the trampoline is (Type an exact answer, using a as needed.)
Mathematics
1 answer:
iVinArrow [24]11 months ago
8 0

Diameter D of the trampoline = 17 feet

The circumference C, of the trampoline is calculated by the formula:

C=\pi D

Put D = 17 feet, π=3.14

\begin{gathered} C=3.14\times17\text{feet} \\ C=53.38\text{feet} \end{gathered}

The cirucmference o

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Answer:

For tree see picture but instead of BG replace all values with RRBBB and see the notes above how to roate the colours instead of the shape roation below just do transition (0,0)(1,0) (1,1).

Then 13 colours minimum change.

This will be 3 + 5 + 4 each colour change = 12 each colour change. instead of doing the 56 each colour rotation below.

Step-by-step explanation:

make 4 bits of paper and label each side -1 and 1 and central 0

above central point vertically label 1 and -1 for transition.

Then change just top one 4x = 4 more

Do the same with 2nd from top = 8 more to include top changing 4x again.

Do the same with 2nd from bottom = 12 more

Do the same with bottom = 16 more.

4+8+12+16 =40

Then repeat the process on side for blocks and we can double up

40+40 = 80.

When drawing tree clearly state columns

Top two are red only change

Top of tree will read in order so where ever you see capital R you will know its a new column for the tree and fill in when you understand the 254 transitions of a 5 column tree. Then change B + R accordingly when you get to row 6. Here you just start changing blue back to the top after row 5

Columns go down and rows go across its a new row you will need

approx 5-6 rows each colour change.

For the ones started for you below its just transition and colour stays where it is.  

R x    RT 45d   RT (1,0) 45   RT (1,1) 45  RT (1,0)

R x    R x

B x    B x

B x    B x

B x    B x

'x' = RED Normal as you keep 0 zero central on all 4 bricks and work with top row as explained below.

Top RED  brick you have to Right side place transition on every 2nd column for each colour and thenyou should find a pattern if youve numbered your papers or brcks to just see how it works. (hanging out one side call this 'off set' or call it T for transition (1.0)

RED Central 'diagonal' call it  '45 degree rotate'

E ABCD RED Normal edge transition its edge so it hangs out

E ABCD RED On edge 45 degree diagonal its edge so it hangs out

2nd only change

S ABCD 1st red normal 2nd red Right side place rotate

S ABCD 1st red right side rotate 2nd red 45 degree rotate

S ABCD 1st red right side rotate 2nd central place 45 degree rotate  

S ABCD 1st red right side rotate 2nd edge Normal edge transition

S ABCD 1st red right side rotate 2nd 45 degree its edge diagonal

2nd is repeated by changing 1st 4x more in bold. see what is now missing for 1st red. and copy the 2nd changes to 1st all whilst rotaing 2nd again in change .

Copy paste the work

Then apply this to 3 + 4 + 5th brick.

As the above shows 10 and when you finish 2nd and 1st it will be 14 total

Then 3 will be 14 again

and 4th brick will be 14 again

and 5th brick will be 14 again

making the transitions and rotations where all bricks in same level placement

14 x 4 = 56 transitions/rotations

Then repeat again for 1 blue at the top change

Then repeat again for 2 blue at the top for change

Then repeat again for 2 blue in the top middle

Then repeat again for 2 blue in the bottom middle

You can label tree

RR = Red rotation

BR = Blue rotation

RRE= Red rotation edge

BRE = Blue rotation

and colour code blue and red pens.

You can label transitions

RT = red transition (1,0)

RT = red transition (1,1) for central

and same for blue etc..

The end result will be 56 x 4 = 224 diagram tree

On ce you learn this it will take just 6 minutes to write out.

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Answer:

Yellow and purple

Step-by-step explanation:

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question 17 on a number line, point s is located at – 3 and point t is located at 9 . what is the location of point r on s t giv
KATRIN_1 [288]

The location of R on the number line will be 15/7.

Number line:

Number line is used for the visual representation of numbers on a straight line.

Basically, Zero (0) is considered to be the origin of a number line. The numbers to the left of 0 are negative numbers and the numbers to the right of 0 are all positive numbers.

Given,

On a number line,

point S is located at – 3 and

point T is located at 9.

Ratio of S and T = 3:4

We need to find the location of point R on S and T.

According to the given details,

The distance from S to T

=> 3 + 9 = 12

Through this we know that,

=> SR + RT = 12 ---------------------(1)

Based on the ratio,

S/T = 3/4

Which is similar to,

SR/RT = 3/4

So,

SR = 3/4 RT -----------(2)

Apply the value of SR on equation (1),

Then

3/4RT + RT = 12

=> 7/4 RT = 12

=> RT = 12 x (4/7)

=> RT = 48/7

Now the location of point R,

=> OT - RT = 9 - 48/7

=> 15/7

Hence "The location of R on the number line will be 15/7".

To know more about Number line Here

brainly.com/question/13425491

#SPJ4

7 0
1 year ago
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