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Agata [3.3K]
1 year ago
5

A manufacturer knows that their items have a normally distributed lifespan, with a mean of 6.9 years, and standard deviation of

1.6 years. If you randomly purchase one item, what is the probability it will last longer than 10 years ?
Mathematics
1 answer:
Lostsunrise [7]1 year ago
7 0

ANSWER

0.9738 or 97.38%

EXPLANATION

Given:

\begin{gathered} mean(\mu)=6.9 \\ Standard\text{ }Deviation(\sigma)=1.6 \end{gathered}

Desired Outcome:

Probability that it will last 10 years

z-score for the sample:

\begin{gathered} z-score=\frac{X-\mu}{\sigma} \\ z-score=\frac{10-6.9}{1.6} \\ z-score=1.9376 \end{gathered}

p-value

For the z-score of 1.9376, the p-value is 0.9738 or 97.38%

Hence, the probability that it will last longer than 10 years if you randonly purchase one item is 97.38%

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6 0
3 years ago
Is1/10 and 3/33 epuivalant
sveta [45]
3/33 can be reduced to 1/11 by dividing by 3 on the top and bottom.
1/11 is not equal to 1/10. Although they have the same numerator or number on top, 1, they don't have the same number in the bottom. 
So they are not equivalent.
Hope this helps. 
7 0
3 years ago
Read 2 more answers
Solve the inequality.2/5 ≥ w -3/5 A. w ≤1/2 B. w ≤ 1 C. w ≥ 1 D. w ≤1/5
Sunny_sXe [5.5K]
We must solve   <span>2/5 ≥ w -3/5.  Note that w is already +, so leave it where it now is.  Add 3/5 to both sides of this inequality:

2/5 + 3/5 </span>≥ w  - 3/5 + 3/5

Then:  1 ≥ w, or w ≤ 1  (answer)
6 0
3 years ago
An open box is to be constructed so that the length of the base is 3 times larger than the width of the base. If the cost to con
natta225 [31]

Answer:

Step-by-step explanation:

Let assume that the volume = 88 cubic feet

Then:

L = 3w --- (1)volume = l \times w \times h \\ \\ 88 =  (3w)   \times w  \times h \\ \\ 3w^2 h= 88 \\ \\ h = \dfrac{88}{3w^2}--- (2) \\ \\

The construction cost now is:

C = 4(l \times w) + 2 ( w  \times h) + 2(l \times h) \\ \\ C = 4(3w^2) + 2(w  \times \dfrac{88}{3w^2}) + 2(3w \times \dfrac{88}{3w^2}) \\\\ C = 12w^2 + \dfrac{176}{3w} + \dfrac{176}{w}

Now, to determine the minimum cost:

\dfrac{dC}{dw}= 0  \\ \\ \implies 24 w - \dfrac{176}{3w^2}- \dfrac{176}{w^2}=0 \\ \\ 24 w ^3 = \dfrac{176}{w^2}(\dfrac{1}{3}+1) \\ \\ 24 w ^3 = \dfrac{176(4)}{3} \\ \\ w^3 = \dfrac{88}{3(3)}

w = \dfrac{88}{3(3)}^{1/3} \ feet

Now;

length = 3 ( \dfrac{88}{3(3)})^{1/3} \ feet

height = ( 88})^{1/3} (3)^{1/3} \ feet

6 0
3 years ago
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Oduvanchick [21]

Answer:

Mathematically speaking, both of these are what are called measures. They are ways of getting at the size of something.

The circumference of a circle is a line, which is one-dimensional, which means it has length but zero width. The area of a circle, in contrast, is two-dimensional. This is the essential difference.

The consequence of this is that circumference is measured in units like centrimetres, or inches, or miles. But area is measured in units like square-centimetres, square inches, or square miles.

Is this what you meant?

6 0
3 years ago
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