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2 years ago

Lyde simplified ( j-8)-2. what error did clyde make, and what is the correct simplified form?

Mathematics

1 answer:

faust18 [17]2 years ago

8 0

The right simplified expression is j - 10

Simplified expression is the simplest form of the equation. We need to group the variable before simplifying equations that have different variables, for example :

a + b + a + c + b

it can be simplified as

a + a + b + b + c = 2a + 2b + c

From the question above, we know that :

( j-8)-2

First, group the same variables

j - 8 - 2

= j + (-8 -2)

= j - 10

Hence, the right simplified form is j - 10 .

For more simplified expression at: brainly.com/question/723406

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What is the value of x and the length of segment DE?

aniked [119]

Answer:

x = 6.6; DE = 16.6

Step-by-step explanation:

Assume the diagram is like the figure below.

1. Calculate the value of x

In a right triangle, the altitude drawn from the right angle to the hypotenuse divides the triangle into two similar triangles.

Thus, ∆CDF ~ ∆FDE, and

$\begin{array}{rcl}\dfrac{CD}{DF} &=& \dfrac{FD}{DE}\\\\\dfrac{5}{9} &=& \dfrac{9}{2x + 3}\\\\5(2x + 3) & = &81\\10x + 15 & = & 81\\10x & = & 66\\x & = & \mathbf{6.6}\\\end{array}$

2. Calculate the length of DE

DE = 2x + 3 = 2(6.6) + 3 = 13.2 + 3 = 16.2

4 0

4 years ago

A road has a 10% grade, meaning increasing 1 unit of rise to every 10 units of run.

finlep [7]

Answer:

Part a) The elevation of the road is $6\°$

Part b) The rise is $0.2\ km$

Step-by-step explanation:

Part a) What is the elevation of the road to the nearest degree?

Let

y-----> the rise of the road ( vertical distance)

x ----> the run of the road (horizontal distance)

we have

y/x=1/10

we know that

The ratio y/x is equal to the tangent of the angle of the elevation of the road

Let

$\theta$ ----> angle of the elevation of the road

$tan(\theta)=y/x$

$tan(\theta)=1/10$

$\theta=arctan(1/10)=6\°$

Part b) If the road is two km long, how much does it rise?

using proportion

$1/10=y/2$

$y=2/10=0.2\ km$

3 0

3 years ago

A monument in the shape of a right triangle sits on a rectangular pedestal that is 5 meters high by 11 meters long. The longest

Vladimir [108]

Based on the information given, there are 2 possibilities:
1) the hypotenuse is the base of the triangles, sitting on the rectangular pedestal
2) the right angle touches the pedestal, with the base equalling the pedestal length

In 1) it is pretty straightforward, because the right angle is the apex (top). The base is 61m, because the longest side in a right is always the hypotenuse.
So now we need the height (h), which will split the triangle into two 45-45-90 triangles with base and h = 30.5 (1/2 the initial base)
This will make the height off the ground = 30.5+5 = 35.5 m

2) with right angle touching the pedestal, we can only assume that the base equals the pedestal length, 11. Then we need the missing side (h), which we can derive from Pythagorean Theorem:
${h}^{2} = {61}^{2} - {11}^{2} \\ \sqrt{({h}^{2})} = \sqrt{({61}^{2} - {11}^{2})} \\ h = \sqrt{({61}^{2} - {11}^{2})} = \sqrt{(3721- 121)} \\ h= \sqrt{3600} = 60$
So in this triangle the height off ground would be 60+5 = 65 m

6 0

4 years ago

Someone help me please

Nadusha1986 [10]

Answer:

15/32

10/9 = 1 1/9

26/15 = 1 11/15

Step-by-step explanation:

3/8 / 4/5 = 3/8 * 5/4 = 15/32

8/9 / 4/5 = 8/9 * 5/4 = 40/36 = 10/9 = 1 1/9

2 3/5 / 1 1/2 = 13/5 / 3/2 = 13/5 * 2/3 = 26/15 = 1 11/15

6 0

3 years ago

Which of the following are always congruent?

GalinKa [24]

Answer: Vertical angles.
Have a good day!

5 0

3 years ago

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