Answer: 1/6
Explanation:
The question is asking how much of the whole circumference is arc AB given that it's central angle is 60°. We can see that the angle is
of the whole. This means that if there were 360 equal sectors, or slices, of the circle, then this angle would take 60 of them.
From this, we can see that if the circumference was divided into 360 equal parts, then the arc would also take up 60 of them, making the arc
, or
.
We could have alternatively seen that the ratio of arc length to the whole circumference would be the same as the ratio of the central angle to the "whole angle" or 360°.
![\frac{Arc\hspace{0.1cm}Length}{Circumference}=\frac{Central\hspace{0.1cm}Angle}{360}](https://tex.z-dn.net/?f=%5Cfrac%7BArc%5Chspace%7B0.1cm%7DLength%7D%7BCircumference%7D%3D%5Cfrac%7BCentral%5Chspace%7B0.1cm%7DAngle%7D%7B360%7D)
Putting in 60 for the central angle, we get
![\frac{Arc\hspace{0.1cm}Length}{Circumference}=\frac{6}{360}=\frac{1}{6}](https://tex.z-dn.net/?f=%5Cfrac%7BArc%5Chspace%7B0.1cm%7DLength%7D%7BCircumference%7D%3D%5Cfrac%7B6%7D%7B360%7D%3D%5Cfrac%7B1%7D%7B6%7D)
The question is asking what fraction of the circumference is the arc length, so let's isolate the arc length by multiplying the circumference to both sides
![Arc\hspace{0.1cm}Length=\frac{1}{6}*Circumference](https://tex.z-dn.net/?f=Arc%5Chspace%7B0.1cm%7DLength%3D%5Cfrac%7B1%7D%7B6%7D%2ACircumference)
This equation in words says that the arc length is one sixth of the circumference, which is exactly what the question is asking.
The highest possible score that you can get is 1600. It is incredibly rare and only around 5% scored in the range of 1400-1600 in the SAT's.
The tension on each segment of the clothesline is : 110 N
<u>Given data : </u>
mass of object = 100 n = 10 kg
Horizontal distance of clothesline = 4 m
middle of clothesline sag s by : 1m
<h3 /><h3>Determine the tension on each segment of clothesline</h3>
<u>First step</u> : calculate the horizontal angle made by the sagging
β = arctan ( 1 m / 2m ) ----- ( 1 )
= arctan ( 0.5 )
≈ 26.57°
Note : Tension in th y axis ( Ty ) = Tsinβ
Therefore :
Tension on each segment can be calculated using the formula below
2Tsinβ - mg = 0
solve for T
T = mg / 2sinβ
= ( 10 * 9.8 ) / 2 * sin 26.57°
= 98 / 0.89
= 110 N
Hence we can conclude that the tension on each segment of the clothesline is : 110 N
Learn more about Tension calculations : brainly.com/question/24994188
Answer: an interview with an agricultural specialist
Explanation: